Write the next 3 terms of AP√27,√48,√75 etc (Revision)

We have a = \sqrt{27} = 3 \sqrt{3} a_{2} = \sqrt{48} = 4 \sqrt{3} a_{3} = \sqrt{75} = 5 \sqrt{3} Now, d = a_{2} - a = 4 \sqrt{3} - 3 \sqrt{3} = \sqrt{3} Now, a_{4} = a_{3} + d = 5 \sqrt{3} + \sqrt{3} = 6 \sqrt{3} = \sqrt{108} a_{5} = a_{4} + d = 6 \sqrt{3} + \sqrt{3} = 7 \sqrt{3} = \sqrt{147} a_{6} = a_{5} + d = 7 \sqrt{3} + \sqrt{3} = 8 \sqrt{3} = \sqrt{192}

Write the next 3 terms of AP​√27,​√48,​√75 etc (Revision)