(x-1/xy)^3 factorize the following

$$\begin{gathered} \mathrm{We} \mathrm{have} \\ {\left(\mathrm{x}-\frac{1}{\mathrm{xy}}\right)}^3 \\ \mathrm{Using} : {\left(\mathrm{a}-\mathrm{b}\right)}^3={\mathrm{a}}^3-3{\mathrm{a}}^2\mathrm{b}+3{\mathrm{ab}}^2-{\mathrm{b}}^3 , \mathrm{we} \mathrm{get} \\ ={\mathrm{x}}^3-3{\mathrm{x}}^2\left(\frac{1}{\mathrm{xy}}\right)+3\mathrm{x}{\left(\frac{1}{\mathrm{xy}}\right)}^2-{\left(\frac{1}{\mathrm{xy}}\right)}^3 \\ ={\mathrm{x}}^3-\frac{3\mathrm{x}}{\mathrm{y}}+\frac{3}{{\mathrm{xy}}^2}-\frac{1}{{\mathrm{x}}^3{\mathrm{y}}^3} \end{gathered}$$
Note : It  was already in factored form .It can only be expanded now which is done above.