x3 - 8x2 + 17x - 10 Share with your friends Share 2 Aman Garg answered this Thus, (x - 1) is a factor of p(x). Now, 3 View Full Answer Apoorva Anant answered this let p(x)= x3-8x2+17x-10Putting x=1 in p(x) we get 0therefore x-1 is a factor of p(x)now x3-8x2+17x-10 can be written as=x3-x2-7x2+7x+10x-10 =x2(x-1)-7x(x-1)+10(x-1) =(x-1){x2-7x+10} (taking x-1 common)=(x-1){x2+5x+2x+10} (Factorising)=(x-1){x(x+5)+2(x+5)}=(x-1)(x+2)(x+5) 3 Devika Krishna answered this =x3-x2-7x2+7x+10x-10=x2(x-1)-7x(x-1)+10(x-1)=(x-1){x2-7x+10} (taking x-1 common)=(x-1){x2+5x+2x+10} (Factorising)=(x-1){x(x+5)+2(x+5)}=(x-1)(x+2)(x+5) -1 Devika Krishna answered this =x3-x2-7x2+7x+10x-10=x2(x-1)-7x(x-1)+10(x-1)=(x-1){x2-7x+10} (taking x-1 common)=(x-1){x2+5x+2x+10} (Factorising)=(x-1){x(x+5)+2(x+5)}=(x-1)(x+2)(x+5) 1