x3 - 8x2 + 17x - 10

Thus, (x - 1) is a factor of p(x). Now,

  • 3

let p(x)= x3-8x2+17x-10

Putting x=1 in p(x) we get 0

therefore x-1 is a factor of p(x)

now  x3-8x2+17x-10 can be written as

=x3-x2-7x2+7x+10x-10 

=x2(x-1)-7x(x-1)+10(x-1)            

=(x-1){x2-7x+10}             (taking x-1 common)

=(x-1){x2+5x+2x+10}      (Factorising)

=(x-1){x(x+5)+2(x+5)}

=(x-1)(x+2)(x+5)

  • 3

=x3-x2-7x2+7x+10x-10

=x2(x-1)-7x(x-1)+10(x-1)

=(x-1){x2-7x+10} (taking x-1 common)

=(x-1){x2+5x+2x+10} (Factorising)

=(x-1){x(x+5)+2(x+5)}

=(x-1)(x+2)(x+5)

  • -1

 =x3-x2-7x2+7x+10x-10

=x2(x-1)-7x(x-1)+10(x-1)

=(x-1){x2-7x+10} (taking x-1 common)

=(x-1){x2+5x+2x+10} (Factorising)

=(x-1){x(x+5)+2(x+5)}

=(x-1)(x+2)(x+5)

 

  • 1
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