XD is a median of triangle XYZ. E is a point on XD such that XE=ED find area of triangle YXD: area of triangle XEZ Share with your friends Share 6 Manbar Singh answered this We know that, a median of a ∆ divides it into 2 ∆'s of equal areas.Since, XD is a median to side YZ of ∆XYZ, thenar∆YXD = ar∆ZXD = 12ar∆XYZ ........1⇒ar∆YXD = 12ar∆XYZ Now, we have XE = ED, soZE is a median to side XD of ∆ZXD.Now, we know that, a median of a ∆ divides it into 2 ∆'s of equal areas.So, ar∆XEZ = ar∆DEZ = 12ar∆ZXD⇒ ar∆XEZ = 12ar∆ZXD⇒ ar∆XEZ = 12×12ar∆XYZ Using 1⇒ar∆XEZ = 14ar∆XYZNow, ar∆YXDar∆XEZ = 12ar∆XYZ14ar∆XYZ = 21 17 View Full Answer