xLof N₂ GAS AT STP contains 3*10²²molecules.
the number of molecules in ozone at STP will be
give the answer with complete explanation

No of molecules = No of moles x N_A ( N_A - Avogadro Number)

No of moles = $\frac{No of molecules}{N_A}$

                   =  $\frac{3 \times {10}^{22}}{6.023 \times {10}^{23}}$
                
                   =  0.4981 x 10^-1  = 0.04981 moles

1 mole of any gas occupies 22.4 L at STP

so 0.04981 mole occupy = ?
                                        =  $\frac{22.4}{1} \times 0.04981$
                               
                                         =       1.115  L               

The volume of N₂ at STP = 1.115 L
If the volume of Nitrogen and Ozone are equal,
22.4 L is occupied by 1 mole.
The no of moles of Ozone present in 1.115 L = ?
                                                     = $\frac{1}{22.4} \times 1.115$

                                                    = 0.04981 moles
No of molecules = mole x N_A

                          = 0.04981 x 6.023 x 10²³

  ​                       = 3 x 10²² 

No of molecules in ozone = 3 x 10²² 

Thus both of them have same no of molecules