yellow seed coat with axial flowers was crossed with yellow seed coat with terminal flowers.mendel got ratio of 6:6:2:2.Show accuracy of ratio
 

Dear student

The ratio 6:6:2:2 is equal to 3:3:1:1

The yellow seed coat and axial flower is dominant over green seed coat and terminal flower.

Let us suppose the genotype of yellow seed coat with axial flowers be (YyTt) and genotype of yellow seed coat with terminal flowers be (Yytt). The cross can be represented as:

Parents                            YyTt              x         Yytt

Gametes                   YT, Yt, yT, yt                 Yt,   yt


Offsprings        YYTt,   YYtt,  YyTt,  Yytt,  YyTt,  Yytt,  yyTt,  yytt

                                                                      Yellow seed            Yellow seed             Green seed                Green seed 
                                                                       Axial flowers       Terminal flowers    Terminal flowers          Terminal flowers
From the given cross, the phenotypic ratio =      3                   :             3                :            1                 :                  1


Hope this information clears your doubt about the topic.

Regards