Zeroes of p(z) = z^2-27 are ??
 

  • 9

    since the polynomial is z2-27 its a quadratic polynomial and will have a maximum of 2 zeroes but this polynomial will have only one zero

    therefore  z2-27=0

    z2=27    

    z=  -_/27

     

     

     

  • 4

 sorry whereever i have written 2 it means 2

  • 1
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