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Syllabus

1.Find the missing frequency f, if the mode of the given data is 154.

Classes

120-130

130-140

140-150

150-160

160-170

170-180

Frequency

2

8

12

f

9

7

plzz give an answer fast....

how to calculate mode if two classes have same and highest frequency (bimodal) ?

what is hit and trial method .

monthly consumption of electricity of some consumers is given below as a distribution. Find the missing frequency(x), if mode is given to be 200 units.

Monthly cosumption(in units ) 90-120 120-150 150-180 180-210 210-240

Number of consumers 20 15 X 75 30

If the median of the distribution is given below is 28.5, find the values of

xandy.Class intervalFrequency0 − 10

5

10 − 20

x20 − 30

20

30 − 40

15

40 − 50

y50 − 60

5

Total

60

IF THE N/2 IS EQUAL TO THE CUMULATIVE FREQUENCY THEN WE WOULD REGARD THAT CLASS AS THE MEDIAN CLASS OR NOT.

if the median of the following frequency distribution is 24. find the missing frequency x :

Age Number of persons

0 - 10 5

10 - 20 25

20 - 30 x

30 - 40 18

40 - 50 7

_{1 }, f_{2}and f_{3}in the following frequency distribution , when it is given taht f_{2 }: f_{3}= 4 : 3 , and mean = 5020-40

40-60

60-80

80-100

17

f

_{1}f

_{2}f

_{3 19}find the missing frequencies if N=100 and median is 32.

marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total

no. of students-10 ,? ,25 ,30 ,? ,10 ,100.

In the step deviation method,

What is the meaning of

u_{i }?The median of the following distribution is 30. Find the missing frequencies f1 and f2:

Class frequency

0-10 10

10-20 10

20-30 f1

30-40 30

40-50 f2

50-60 10

Total 100

Find the value of f1 from the following data if it's mode is 65:

Class frequency

0-20 6

20-40 8

40-60 f1

60-80 12

80-100 6

100-120 5

Where frequency 6,8, f1, and 12 are in ascending order.

the mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?

Mode and mean of a data are 12k and 15k. Median of the data is

how to find the mean if the class intervals are unequal??

like fr e- 0-10,10-30,30-35....

10. If median = 15 and mean = 16, find mode of the distributionThe mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______

how to find xi?

The median from the table is

value 7, 8, 9, 10, 11, 12 ,13

frequency 2, 1, 4, 5, 6, 1, 3

Q1) among the following which is not the measure of central tendency?

A) Mean B) Median C) Mode D) range

Q2) among the following which is the best measure of central tendency?

A) Mean B) Median C) Mode

What is the formula to use median when more than ogive is given?

The mean of the following data is 38.2. Find the missing frequencies f1 and f2 if the total frequency is 50.

Classes

0-10

10-20

20-30

30-40

40-50

50-60

60-70

Frequency

4

4

F1

10

F2

8

5

median.

Classes 20-30 30-40 40-50 50-60 60-70 70-80 80-90

frequency 10 8 12 24 6 25 15

A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Number of days0 − 6

6 − 10

10 − 14

14 − 20

20 − 28

28 − 38

38 − 40

Number of students11

10

7

4

4

3

1

Find the median of the following data.

Wages ( in rupees ) :More than 150 , More than 140 , More than 130 , More than 120 , More than 110 , More than 100 , More than 90 . More than 80.No.of workers : NIL ,12,27,60,105,124,141,150.Marks Below 10 Below 20 Below 30 Below 40 Below 50 Below 60 Below 70 Below 80 Below 90 Below 100

No. of students 5 9 17 29 45 60 70 78 83 85

…………………. Is called a positional average.

3 Median = Mode + 2 Mean

please proof it.

For the given data with 120 observations, the less than ogive and more than ogive intersect at (42.5,60). The median of the data is :

A ) 60

B) 42.5

C) 120

D) 21.25

In a continuous frequency distribution, the median of the data is 21.If each observation is increased by 5 find the new median

height 150-156 156-162 162-168 168-174 174-180

no.students 4 7 15 8 6

find mean height.

The mean and median of same data are 24 and 26 respectively. The value of mode is ?

Classes Frequency

0-5 7

5-10 6

10-15 f

15-20 4

20-25 3

a) f <8

b) f

>8c) f > 8 only

d) f<7

marks number of students

0 and above 80

10 and above 77

20 and above 72

30 and above 65

40 and above 55

50 and above 43

60 and above 28

70 and above 16

80 and above 10

90 and above 8

100 and above 0

in a grouped frequency distribution,the class with the maximum frequency is called?

a.mean class b.median class c.modal class d.distribution class

The following distribution gives the daily income of 50 workers of a factory.

Daily income (in Rs)100 − 120

120 − 140

140 − 160

160 − 180

180 − 200

Number of workers12

14

8

6

10

Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.

If the median I.Q of the students is 135, find the missing frequencies f1 and f2 in the following frequency distribution for 220 students:

I.Q 100-110 110-120 120-130 130-140 140-150 150-160 160-170 170-180

Number of students 15 35 f1 f2 33 23 19 8

the mean of first n odd natural numbers is n2/81,then n=

The median of the following incomplete frequency distribution is 4 :

x= 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8

f= 2 , 3 , 4 , 1 , 2 , 4 , 2 , x

the frequency of 8 is : A) 1 B) 2 C) 3 D) 4 plz ans fastt....

if the mean of the following frequency distribution is 91, find the missing frequency x and y :

classes frequency

0 - 30 12

30-60 21

60 - 90 x

90 -120 52

120 - 150 y

150 - 180 11

total 150

class 0-20 20-40 40-60 60-80 80-100 100-120

frequency14 x 24 32

10 2

The mean of n observations is X . IF the first item is increased by 1, second by 2 and so on, then the new mean is:

1. X+n

2. X+n/2

3. X+(n+1)/2

4. X+(n-1)/2

classes frequency

0-100 8

100- 200 12

200-300 x

300-400 20

400-500 14

500-600 7

class frequency

40-50 5

50-60 x

60-70 15

70-80 2

80-90 7

9. Find the mean age in years form a frequency distribution given below:

how do we find mean using step deviation method if the classes are unequal?

should we make the classes equal in such a case?

_{i}=100 , h=10 and f_{i}u_{i}= -30 , then find the mean of following distribution.PLEASE ANSWER FAST.

During the medical check-up of 35 students of a class, their weights were recorded as follows:

Weight (in kg)Number of studentsLess than 38

0

Less than 40

3

Less than 42

5

Less than 44

9

Less than 46

14

Less than 48

28

Less than 50

32

Less than 52

35

Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.

In a school 85 boys and 35 girls appeared in a public examination . The mean marks of the boys were found to be 40 % whereas the mean marks of the girls were 60% . Determine the average marks % of the school.

Class interval Frequency0-10 10

10-20 20

20-30 x

30-40 40

40-50 y

50-60 25

60-70 15

d

_{i}is the deviation of x_{i }from assumed mean a.If mean = x + ∑f

_{i}d_{i}/∑f_{i}, then x is(in percent)

is the ans median class 60-70 and modal class 50-60??

Find the sum of deviations of the variate values 3, 4, 6, 7, 8, 14 from

their mean.

Class interval Frequency10-20 12

20-30 30

30-40 f1

40-50 65

50-60 f2

60-70 25

70-80 18

no links plz.

if the arithmetic mean of the following distribution is 56, find the missing frequencies f1 and f2

the median of the data is 525. find x and y, if total frequency is 100

class 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000

frequeency 2 5 x 12 17 20 y 9 7 4

Height 160-162 163-165 166-168 169-171 172-174

frequency 15 117 x 118 14if the median of distribution is 167 . find the value of 'x'9. If the mean of the distribution is 57.6 and the sum of its observations is 50, find the missing

The mean of the following frequency dristibution is 50. Find the value of

ppXi 35 38 40 42 44

fi 5 9 10 7 2

Height No. of students.

125-130 2

130-135 4

135-140 x

140-145 y

145-150 8

150-155 9

155-160 5

how can we find the median by only less than ogive curve?

calculate the median from the following data

class interval frequency

130-1405

140-150 9

150-160 17

160-170 28

170-180 24

180-190 10

190-200 7

The median of the following data is 32.5.find the value of x and y

class interval f

0-10 x

10-20 5

20-30 9

30-40 12

40-50 y

50-603

60-70 2

total 40

The following table shows the marks obtained by 100 students of class X in a school during a particular academic session. Find the mode of this distribution.

Marks No. of studentsLess than 10 7

Less than 20 21

Less than 30 34

Less than 40 46

Less than 50 66

Less than 60 77

Less than 70 92

Less than 80 100

(in years)

(A)

(B)

Find the modal age of employees in factory A and B.

Find the mean, mode and median for the following data.

The median of the following data is 20.75. Find the missing frequencies x and y, if the total frequency is 100.

Class interval:-0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40

Frequencies: -7 10 x 13 y 10 14 9

1. Observe the information's in the following cumilative frequency table

no. of days absentless than 5

less than 10

less than 15

less than 20

less than 25

less than 30

less than 35

less than 40

less than 45

No. of students29224465582634644650653655Q.. Draw a 'less than' ogive and 'more than' ogive to represent the above data .

Q... Find median for the above data by interpreting the graph.

Q...why regularity is essential in students life (VBQ)

how to find the median class?

family size:0-4,4-8,8-12,12-16,16-20

number of families:8,14,12,4,2

find median and mode.

How to find missing frequency if the mode of the given data is given.

frequency is 80.

How to convert a

LESS THAN OGIVEand it'sCFinto the Frequency distribution?Compute the median for the following data :

Marks No. of students

More than or equal to 70 0

More than or equal to 60 11

More than or equal to 50 23

More than or equal to 40 43

More than or equal to 30 58

More than or equal to 20 72

More than or equal to 10 82

Find the class marks of classes 10 - 25 and 35 - 55.(A)21.10

(B)19.67

(C)20.10

(D)20.67

If the mean of the following distributions is 27, Find the value of p

If the less than ogive and more than ogive intersect each other at ( 20.5,15.5 ), then the median of the given data is :

A ) 36.0 B) 20.5 C ) 15.5 D ) 5.5

Calculate the median for the following:

Class Interval: 110-120, 120-130, 130-140, 140-150, 150-160, 160-170, 170-180, 180-190, 190-200.

f: 6, 25, 48, 72, 116, 60, 38, 22, 3

The mean of the following data is 53, find the missing frequencies.

age in years -- 0-20, 20-40 40-60 60-80, 80-100

number of people--- 15, f1, 21, f2, 17, 100

Find the missing frequency if Mode of the following data is 52 . Classes10 -25 25 -40 40 -55 55 -70 70 -85 85 -100 with Frequency 2,3,7, f ,6,6 respectively

Total = 50

height in cm frequency cumulative frequency

150-155 12 a

155-160 b 25

160-165 10 c

165-170 d 43

170-175 e 48

175-180 2 f

Class 0 – 20 20 – 40 40 – 60 60 – 80 80 –100 100 –120

Frequency 6 8 f 12 6 5

8. The mean of the following distribution is 53. Calculate missing frequencies

the class mark of classes in a distribution arer 6.10.14.18.22.26.30. find

a) class size

b) lower limit of second class

c) upper lmit of last class

d) third class