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1.Find the missing frequency f, if the mode of the given data is 154.
Classes
120-130
130-140
140-150
150-160
160-170
170-180
Frequency
2
8
12
f
9
7
plzz give an answer fast....
what is hit and trial method .
If the median of the distribution is given below is 28.5, find the values of x and y.
Class interval
0 − 10
5
10 − 20
x
20 − 30
20
30 − 40
15
40 − 50
y
50 − 60
Total
60
if the median of the following frequency distribution is 24. find the missing frequency x :
Age Number of persons
0 - 10 5
10 - 20 25
20 - 30 x
30 - 40 18
40 - 50 7
find the missing frequencies if N=100 and median is 32.
marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total
no. of students-10 ,? ,25 ,30 ,? ,10 ,100.
The median of the following distribution is 30. Find the missing frequencies f1 and f2:
Class frequency
0-10 10
10-20 10
20-30 f1
30-40 30
40-50 f2
50-60 10
Total 100
the mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?
how to find the mean if the class intervals are unequal??
like fr e- 0-10,10-30,30-35....
The mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______
how to find xi?
how to calculate mode if two classes have same and highest frequency (bimodal) ?
What is the formula to use median when more than ogive is given?
A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.
Number of days
0 − 6
6 − 10
10 − 14
14 − 20
20 − 28
28 − 38
38 − 40
Number of students
11
10
4
3
1
3 Median = Mode + 2 Mean
please proof it.
In a continuous frequency distribution, the median of the data is 21.If each observation is increased by 5 find the new median
The mean and median of same data are 24 and 26 respectively. The value of mode is ?
The following distribution gives the daily income of 50 workers of a factory.
Daily income (in Rs)
100 − 120
120 − 140
140 − 160
160 − 180
180 − 200
Number of workers
14
6
Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.
Find the value of f1 from the following data if it's mode is 65:
0-20 6
20-40 8
40-60 f1
60-80 12
80-100 6
100-120 5
Where frequency 6,8, f1, and 12 are in ascending order.
the mean of first n odd natural numbers is n2/81,then n=
if the mean of the following frequency distribution is 91, find the missing frequency x and y :
classes frequency
0 - 30 12
30-60 21
60 - 90 x
90 -120 52
120 - 150 y
150 - 180 11
total 150
The mean of n observations is X . IF the first item is increased by 1, second by 2 and so on, then the new mean is:
1. X+n
2. X+n/2
3. X+(n+1)/2
4. X+(n-1)/2
how do we find mean using step deviation method if the classes are unequal?
should we make the classes equal in such a case?
During the medical check-up of 35 students of a class, their weights were recorded as follows:
Weight (in kg)
Less than 38
0
Less than 40
Less than 42
Less than 44
Less than 46
Less than 48
28
Less than 50
32
Less than 52
35
Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.
Find the sum of deviations of the variate values 3, 4, 6, 7, 8, 14 fromtheir mean.
the median of the data is 525. find x and y, if total frequency is 100
class 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000
frequeency 2 5 x 12 17 20 y 9 7 4
9. If the mean of the distribution is 57.6 and the sum of its observations is 50, find the missing
The mean of the following frequency dristibution is 50. Find the value of p
In a school 85 boys and 35 girls appeared in a public examination . The mean marks of the boys were found to be 40 % whereas the mean marks of the girls were 60% . Determine the average marks % of the school.
how can we find the median by only less than ogive curve?
The median of the following data is 32.5.find the value of x and y
class interval f
0-10 x
10-20 5
20-30 9
30-40 12
40-50 y
50-603
60-70 2
total 40
The following table shows the marks obtained by 100 students of class X in a school during a particular academic session. Find the mode of this distribution.
Marks No. of students
Less than 10 7
Less than 20 21
Less than 30 34
Less than 40 46
Less than 50 66
Less than 60 77
Less than 70 92
Less than 80 100
Find the mean, mode and median for the following data.
The median of the following data is 20.75. Find the missing frequencies x and y, if the total frequency is 100.
Class interval:-0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40
Frequencies: -7 10 x 13 y 10 14 9
how to find the median class?
How to find missing frequency if the mode of the given data is given.
How to convert a LESS THAN OGIVE and it's CF into the Frequency distribution?
Find the class marks of classes 10 - 25 and 35 - 55.
If the less than ogive and more than ogive intersect each other at ( 20.5,15.5 ), then the median of the given data is :
A ) 36.0 B) 20.5 C ) 15.5 D ) 5.5
If the mean of the following distributions is 27, Find the value of p
The mean of the following data is 53, find the missing frequencies.
age in years -- 0-20, 20-40 40-60 60-80, 80-100
number of people--- 15, f1, 21, f2, 17, 100
the class mark of classes in a distribution arer 6.10.14.18.22.26.30. find
a) class size
b) lower limit of second class
c) upper lmit of last class
d) third class
E.g: 9876543210, 01112345678
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Syllabus
1.Find the missing frequency f, if the mode of the given data is 154.
Classes
120-130
130-140
140-150
150-160
160-170
170-180
Frequency
2
8
12
f
9
7
plzz give an answer fast....
what is hit and trial method .
If the median of the distribution is given below is 28.5, find the values of x and y.
Class interval
Frequency
0 − 10
5
10 − 20
x
20 − 30
20
30 − 40
15
40 − 50
y
50 − 60
5
Total
60
if the median of the following frequency distribution is 24. find the missing frequency x :
Age Number of persons
0 - 10 5
10 - 20 25
20 - 30 x
30 - 40 18
40 - 50 7
find the missing frequencies if N=100 and median is 32.
marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total
no. of students-10 ,? ,25 ,30 ,? ,10 ,100.
The median of the following distribution is 30. Find the missing frequencies f1 and f2:
Class frequency
0-10 10
10-20 10
20-30 f1
30-40 30
40-50 f2
50-60 10
Total 100
the mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?
how to find the mean if the class intervals are unequal??
like fr e- 0-10,10-30,30-35....
The mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______
how to find xi?
how to calculate mode if two classes have same and highest frequency (bimodal) ?
What is the formula to use median when more than ogive is given?
median.
Classes 20-30 30-40 40-50 50-60 60-70 70-80 80-90
frequency 10 8 12 24 6 25 15
A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.
Number of days
0 − 6
6 − 10
10 − 14
14 − 20
20 − 28
28 − 38
38 − 40
Number of students
11
10
7
4
4
3
1
Marks Below 10 Below 20 Below 30 Below 40 Below 50 Below 60 Below 70 Below 80 Below 90 Below 100
No. of students 5 9 17 29 45 60 70 78 83 85
3 Median = Mode + 2 Mean
please proof it.
In a continuous frequency distribution, the median of the data is 21.If each observation is increased by 5 find the new median
The mean and median of same data are 24 and 26 respectively. The value of mode is ?
marks number of students
0 and above 80
10 and above 77
20 and above 72
30 and above 65
40 and above 55
50 and above 43
60 and above 28
70 and above 16
80 and above 10
90 and above 8
100 and above 0
The following distribution gives the daily income of 50 workers of a factory.
Daily income (in Rs)
100 − 120
120 − 140
140 − 160
160 − 180
180 − 200
Number of workers
12
14
8
6
10
Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.
Find the value of f1 from the following data if it's mode is 65:
Class frequency
0-20 6
20-40 8
40-60 f1
60-80 12
80-100 6
100-120 5
Where frequency 6,8, f1, and 12 are in ascending order.
the mean of first n odd natural numbers is n2/81,then n=
if the mean of the following frequency distribution is 91, find the missing frequency x and y :
classes frequency
0 - 30 12
30-60 21
60 - 90 x
90 -120 52
120 - 150 y
150 - 180 11
total 150
The mean of n observations is X . IF the first item is increased by 1, second by 2 and so on, then the new mean is:
1. X+n
2. X+n/2
3. X+(n+1)/2
4. X+(n-1)/2
class frequency
40-50 5
50-60 x
60-70 15
70-80 2
80-90 7
how do we find mean using step deviation method if the classes are unequal?
should we make the classes equal in such a case?
During the medical check-up of 35 students of a class, their weights were recorded as follows:
Weight (in kg)
Number of students
Less than 38
0
Less than 40
3
Less than 42
5
Less than 44
9
Less than 46
14
Less than 48
28
Less than 50
32
Less than 52
35
Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.
Class interval Frequency
0-10 10
10-20 20
20-30 x
30-40 40
40-50 y
50-60 25
60-70 15
Find the sum of deviations of the variate values 3, 4, 6, 7, 8, 14 from
their mean.
Class interval Frequency
10-20 12
20-30 30
30-40 f1
40-50 65
50-60 f2
60-70 25
70-80 18
no links plz.
the median of the data is 525. find x and y, if total frequency is 100
class 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000
frequeency 2 5 x 12 17 20 y 9 7 4
9. If the mean of the distribution is 57.6 and the sum of its observations is 50, find the missing
The mean of the following frequency dristibution is 50. Find the value of p
In a school 85 boys and 35 girls appeared in a public examination . The mean marks of the boys were found to be 40 % whereas the mean marks of the girls were 60% . Determine the average marks % of the school.
how can we find the median by only less than ogive curve?
The median of the following data is 32.5.find the value of x and y
class interval f
0-10 x
10-20 5
20-30 9
30-40 12
40-50 y
50-603
60-70 2
total 40
The following table shows the marks obtained by 100 students of class X in a school during a particular academic session. Find the mode of this distribution.
Marks No. of students
Less than 10 7
Less than 20 21
Less than 30 34
Less than 40 46
Less than 50 66
Less than 60 77
Less than 70 92
Less than 80 100
Find the mean, mode and median for the following data.
The median of the following data is 20.75. Find the missing frequencies x and y, if the total frequency is 100.
Class interval:-0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40
Frequencies: -7 10 x 13 y 10 14 9
how to find the median class?
How to find missing frequency if the mode of the given data is given.
How to convert a LESS THAN OGIVE and it's CF into the Frequency distribution?
Find the class marks of classes 10 - 25 and 35 - 55.
If the less than ogive and more than ogive intersect each other at ( 20.5,15.5 ), then the median of the given data is :
A ) 36.0 B) 20.5 C ) 15.5 D ) 5.5
If the mean of the following distributions is 27, Find the value of p
The mean of the following data is 53, find the missing frequencies.
age in years -- 0-20, 20-40 40-60 60-80, 80-100
number of people--- 15, f1, 21, f2, 17, 100
Total = 50
height in cm frequency cumulative frequency
150-155 12 a
155-160 b 25
160-165 10 c
165-170 d 43
170-175 e 48
175-180 2 f
the class mark of classes in a distribution arer 6.10.14.18.22.26.30. find
a) class size
b) lower limit of second class
c) upper lmit of last class
d) third class