Page No 33:
Answer:
(i)
(ii)
(iii)
(iv)
(v)
Page No 33:
Question 2:
(i)
(ii)
(iii)
(iv)
(v)
Answer:
(i)
(ii)
(iii)
(iv)
Page No 33:
Question 3:
(i)
(ii)
(iii)
(iv)
Answer:
(i)
â
(ii)
â
(iii)
â
Page No 33:
Question 4:
(i)
â
(ii)
â
(iii)
â
Answer:
(i)
(ii)
(iii)
Page No 33:
Question 5:
(i)
(ii)
(iii)
Answer:
Page No 33:
Question 6:
Answer:
Page No 33:
Question 7:
Answer:
Page No 33:
Question 8:
Answer:
(i)
â
(ii)
(iii)
Page No 34:
Question 9:
(i)
â
(ii)
(iii)
Answer:
Consider the left side:
Given:
Comparing the powers:
Page No 34:
Question 10:
Consider the left side:
Given:
Comparing the powers:
Answer:
Given:
Page No 34:
Question 11:
Given:
Answer:
Let the required number be .
The greatest common divisor for the numerator and the denominator is 3.
Page No 34:
Question 12:
Let the required number be .
The greatest common divisor for the numerator and the denominator is 3.
Answer:
Let the number be .
Page No 34:
Question 13:
Let the number be .
Answer:
Given:
Page No 36:
Question 1:
Given:
Answer:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Page No 36:
Question 2:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Answer:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Page No 36:
Question 3:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Answer:
(i) The height of the Mount Everest is 8848 m.
In standard form, we have:
â.
(ii) The speed of light is 300000000 m/s.
In standard form, we have:
(iii) The SunEarth distance is 149600000000 m.
In standard form, we have:
Page No 36:
Question 4:
(i) The height of the Mount Everest is 8848 m.
In standard form, we have:
â.
(ii) The speed of light is 300000000 m/s.
In standard form, we have:
(iii) The SunEarth distance is 149600000000 m.
In standard form, we have:
Answer:
Mass of the Earth =
Now,
So, the mass of the Earth can also be written as .
Mass of the Moon =
Sum of the masses of the Earth and the Moon:
Page No 36:
Question 5:
Mass of the Earth =
Now,
So, the mass of the Earth can also be written as .
Mass of the Moon =
Sum of the masses of the Earth and the Moon:
Answer:
(i)
(ii)
(iii)
(iv)
(v) 0.00000165 = (2-8) = 1.65×10-6
(vi) 0.00000000689 = (2-11)= 6.89×10-9
Page No 36:
Question 6:
(i)
(ii)
(iii)
(iv)
(v) 0.00000165 = (2-8) = 1.65×10-6
(vi) 0.00000000689 = (2-11)= 6.89×10-9
Answer:
(i)
(ii)
(iii)
Page No 36:
Question 7:
(i)
(ii)
(iii)
Answer:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Page No 37:
Question 1:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Answer:
(c)
Page No 37:
Question 2:
(c)
Answer:
(d)
Page No 37:
Question 3:
(d)
Answer:
(b)
Page No 37:
Question 4:
(b)
Answer:
(d)
Page No 37:
Question 5:
(d)
Answer:
(b)
Page No 37:
Question 6:
(b)
Answer:
(c) 29
Page No 37:
Question 7:
(c) 29
Answer:
(a)
Page No 37:
Question 8:
(a)
Answer:
(a)
Page No 37:
Question 9:
(a)
Answer:
(d) 3
Page No 37:
Question 10:
(d) 3
Answer:
(d) 2
⇒ 23x-1 = 42 -10
⇒23x-1 = 32
⇒ 23x-1 = 25
⇒ 3x-1 = 5
⇒ 3x = 6
Therefore,x = 2
Page No 37:
Question 11:
(d) 2
⇒ 23x-1 = 42 -10
⇒23x-1 = 32
⇒ 23x-1 = 25
⇒ 3x-1 = 5
⇒ 3x = 6
Therefore,x = 2
Answer:
(c) 1
Using the law of exponents :
Page No 38:
Question 12:
(c) 1
Using the law of exponents :
Answer:
(c)
Page No 38:
Question 13:
(c)
Answer:
(d)
Page No 38:
Question 14:
(d)
Answer:
(b)
Page No 38:
Question 15:
(b)
Answer:
(c)
Page No 38:
Question 16:
(c)
Answer:
(b)
Page No 38:
Question 17:
(b)
Answer:
(a) 3.67
Page No 39:
Question 1:
(a) 3.67
Answer:
(i)
(ii)
(iii)
(iv)
(v) Using the property , we have:
Page No 39:
Question 2:
(i)
(ii)
(iii)
(iv)
(v) Using the property , we have:
Answer:
Page No 39:
Question 3:
Answer:
Page No 39:
Question 4:
Answer:
Let the number be .
Page No 39:
Question 5:
Let the number be .
Answer:
Let the number be .
Page No 39:
Question 6:
Let the number be .
Answer:
(i)
(ii)
(iii)
(iv)
Page No 39:
Question 7:
(i)
(ii)
(iii)
(iv)
Answer:
(c)
Page No 39:
Question 8:
(c)
Answer:
(b)
Page No 39:
Question 9:
(b)
Answer:
(c)
Page No 39:
Question 10:
(c)
Answer:
(d) 3
Page No 39:
Question 11:
(d) 3
Answer:
(c) 1
Using the law of exponents, which says we get:
Page No 39:
Question 12:
(c) 1
Using the law of exponents, which says we get:
Answer:
(d)
Page No 39:
Question 13:
(d)
Answer:
(c)
Page No 40:
Question 14:
(c)
Answer:
(i) The standard form of 36000 is .
(ii) The standard form of 0.0000123 is .
(iii)
â
(iv)
â
(v)
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