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what must be subtracted from 8x

^{4}+14x^{3}-2x^{2}+7x-8 so that the resulting polynomial is exactly divisible by 4x^{2}+3x-2.How to factorise x^5-y^5 ?????

^{2}one of the factors of (a

^{2}-b^{2}) (c^{2}-d^{2}) -4abcd isa)(ac-bd+bc+ad)

b)ac+bd+bc+ad

c)ab+bd-bc-ad

explain andd then give your answer.

factorise:

(ax+by)

^{2}+(bx-ay)^{2}- Find the values of 'm' for which x2 + 3xy + x + my - m has two linear factors in x and y, with integer coefficients.

^{2 }+ 1/x^{2}= 34 , find the value of x + 1/x.Factorise : a

^{2}+ b^{2}- 2 (ab - ac + bc)^{2}+xy+y^{2 }?P

^{2}+6P +8FACTORISE

(IT'S AN URGENT, ANSWER AS FAST AS U GET THIS)

factorise-

x

^{4}-(x-z)^{4}factorise: 3+23z-8z

^{2}25

a^{2}− 4b^{2}+ 28bc− 49c^{2}Factorise - 12x + 36

Factorise the following expressions.

(i)

a^{2}+ 8a+ 16(ii)

p^{2}− 10p+ 25(iii) 25

m^{2}+ 30m+ 9(iv) 49

y^{2}+ 84yz+ 36z^{2}(v) 4

x^{2}− 8x+ 4(vi) 121

b^{2}− 88bc+ 16c^{2}(vii) (

l+m)^{2}− 4lm(Hint: Expand (l+m)^{2}first)(viii)

a^{4}+ 2a^{2}b^{2}+b^{4}: [ (p+q)Factorise^{2 }- (a- b)^{2}] +p +q - a+ bif x = 3

rn^{1/3 }+ 3^{-1/3}, then^{}whatis the value of 3x^{3}- 9x ?a) 12 b) 9 c)15 d) 10 how??

^{4}+9p^{2}q^{2}+ 81q^{4}factorise 2)AB + BA=(B+1)CB

7x^2-19x-6

Expert please solve it fast

Factorise :2a + 6b - 3 (a + 3b)^{2}^{2}-81(x-2y)^{2}Find the common factors of the terms

(i) 12

x, 36(ii) 2

y, 22xy(iii) 14

pq, 28p^{2}q^{2}(iv) 2

x, 3x^{2}, 4(v) 6

abc, 24ab^{2}, 12a^{2}b(vi) 16

x^{3}, −4x^{2}, 32x(vii) 10

pq, 20qr, 30rp(viii) 3

x^{2}y^{3}, 10x^{3}y^{2}, 6x^{2}y^{2}z^{2}Factorise

ab2+(a-1)b-1

^{3}-8Factorise: 14 (3y-5z)

^{3}+7(3y-5z)^{ 2}Factorize-

abc + ab + bc + ca + a + b + c + 1

how we'll solve this by using identity

Factorise the expressions and divide them as directed.

(i) (

y^{2}+ 7y+ 10) ÷ (y+ 5)(ii) (

m^{2}− 14m− 32) ÷ (m+ 2)(iii) (5

p^{2}− 25p+ 20) ÷ (p− 1)(iv) 4

yz(z^{2}+ 6z− 16) ÷ 2y(z+ 8)(v) 5

pq(p^{2}−q^{2}) ÷ 2p(p+q)(vi) 12

xy(9x^{2}− 16y^{2}) ÷ 4xy(3x+ 4y)(vii) 39

y^{3}(50y^{2}− 98) ÷ 26y^{2}(5y+ 7)(x-1)(x-2)(x

^{2}-9x+14)-------------------------

(x-7) (x

^{2}-3x+2)The answer provided in the NCERT solutions of Class VIII Maths , Chapter - Factorisation Ex - 14.3 Question 5) vii) is not given completely.Why???

the ratio of two sides of a parallelogram are as 3:5 and its perimeter is 60cm.find the measures of all the sides

25a

^{2}4b^{2 }+ 28bc 49c^{2}^{factorise it.}Find the difference between the simple interest and the compound interest on Rs. 5000 for 2 years at 9% per annum.? Please answer soon its urgent.

Q.1(X-2y)2+(8y-4x)

factorise completely 256x^4 -81y^4

(x+5 )

^{ 2}- 4(x+5)factorise:6p

^{2}+11p-10:Factorisea^{4}- ( 2b + c)^{4}a

^{4-2a}^{2b2+b4 .factorise it}If (a/b) + (b/a) = 2, then find (a/b)^{10}- (b/a)^{10}.factorise this -

z-7+7xy-xyzFactorise :-

15pq + 15 + 9q + 25p

please factorise :- 25x

^{2}-4y^{2}+ 28yz - 49z^{2}I got All India Rank 127 in FTRE(Fiitjee Talent Reward Exam) held on 25Dec 2011. I got 100% on all things and 60000 cash prize. and in NSAT 2011 held on 4 Dec 2011 i got All India Rank 36 and zonal rank 3 with 100% scholarship on tuition fee.

the simple interest on a sum of money for 3 years at 6 2/3%[ mixed fraction] per annum is rs 6750 whatt will be the compound interest on the same sum at the same rate for the same period, compounded annualy ans=rs 7210

Factorise: 16x

^{5}- 144x^{3}x

^{2}-y^{2}-2yz-z^{2}factorize

4x

^{4}+ 1please factorize :

a4+3a2+4

A) 15x^4 + 6x^3 - 7x^2 + 11x - 21 by 3x^2 + 4

It's from ch Factorisation ?

Factorise

(i)

a^{4}−b^{4}(ii)

p^{4}− 81(iii)

x^{4}− (y+z)^{4}(iv)

x^{4}− (x−z)^{4}(v)

a^{4}− 2a^{2}b^{2}+b^{4}If x-y=12 and xy=25/4,find x+y

factorize the following equation:

(x-2y)

^{2}+4x-8yFactorise (a) 16a

^{2}+88a+121(b) 144-24x+x

^{2}solve:-

44(x

^{4}- 5x^{3}-24x^{2)}divided by 11x(x-8)^{2}Factorise the expression as directed:

(5p2 - 25p + 20)

~~:~~(p - 1)factorise the following

64a

^{2}+80ab+25b^{2}(x-1)(x+3)(x-2)(x-6)+96

Factorise

(i) 4

p^{2 }− 9q^{2}(ii) 63

a^{2}− 112b^{2}(iii) 49

x^{2}− 36(iv) 16

x^{5}− 144x^{3}(v) (

l+m)^{2}− (l−m)^{2}(vi) 9

x^{2}y^{2}− 16(vii) (

x^{2}− 2xy+y^{2}) −z^{2}(viii) 25

a^{2}− 4b^{2 }+ 28bc− 49c^{2}is . a. (xy + yz + xz)(a + b + c)

b. (ab + bc + ac)(x + y + z)

c. (x + y + z)(a + b + c)

d. (a + b + c)(2x + 2y + 2z)

12(2x-3y)^2-16(3y-2x)

Q) What must be added to ${a}^{4}+2{a}^{3}-2{a}^{2}+a-1$ so that the resulting polynomial exactly divisible by ${a}^{2}+2a-3$.

factorize:

x(a-3)+y(3-a)

facotorise

(2x-3)^{2}-8x +12p

^{2}-p-72Factorise the expression q^{2}- 10q + 21Factorise:-

(2p-3q)

^{2 }- (3p + 2q)^{2}Factorise 6xy - 4y + 6 -9x by regrouping method. Please explain the regrouping of 6-9x to get the common factor 3x-2 as it is the same obtained in the 6xy -4y

Find the value of 'p' if:-

(i) 143p = (76)

^{2}- (67)^{2}3(a-2b)2 - 5(a - 2b)

Factorise : a

^{4}+ 2a^{2}b^{2}+ b^{4}Please Give An Explanation.

what is a

^{2}+ (ab)^{2}+ b^{2}divided by a + ab+ b? please answer as soon as possible!! :D^{2}-10x^{2}y+16x^{2}y^{2}+2xyy

^{2}+ y -72^{2}+y^{2}+14x-7y-4xy+12 Factorise it.Factorise:

24d cube -16d square + 12d -8