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Syllabus

1) ABCD is a paralellogram. X and Y are mid points of BC and CD respectively.Prove that area (AXY) = 3/8 area(paralellogram ABCD)

2) In a triangle ABC P and Q are respectively the mid points of AB and BC and R is the mid point of AP. Prove that:

1) area(PRQ) =1/2 area(ARC)

2) area(RQC) = 3/8 area(ABC)

3) area(PBQ) = area(ARC)

ABCD is a trapezium in which AB is parallel to DC. DC=30 cm. and AB=50cm. if X and Y are respectively the mid points of AD and BC, prove that (

Nine times the area of DCYX= seven times the area of XYBA.)If a planar region formed by a figure T is made up of two non overlapping planar regions formed by figures P and Q ,then ar(P)+ar(Q),where ar(X) denotes the area of figure X

Thank you

if the medians of a triangle ABC intersect at G show that ar ( AGB ) = ar(AGC)=ar(BGC)=1/3 ar(ABC).

prove that two triangles having the same base (or equal bases) and equal areas lie between the same parallels.

Let ABC be an equilateral triangle in which coordinates of B and C are (5,0) and (-5,0) respectively . Find the coordinates of the oint A.

prove that median divides triangle into two equal parts

The median BE and CF of a triangle ABC intersect at G. prove that area of triangle-GBC = area of quadrilateral AFGE.

1-krishnasarp 2-parmanand 3-janmanth 4-bekhatke 5-bailghari

Diagonals AC and BD of trapezium ABCD with AB||DC intersect each other at O.

prove that ar(AOD) = ar (BOC)?

if perimeter of a right angled triangle is six times its smallest side,then the three sides of this triangle are in the ratio of

prove that the diagonals of a parallelogram divides into four triangle of an equal area

If a triangle is divided into four pieces with areas 8 , 5 , 10 and x then find x.

ABCD is a parallelogram in which BC is produced to E such that CE = BC(Fig. 9.17). AE intersects CD at F.If ar (DFB) = 3 cm2, find the area of the parallelogram ABCD.

in the given figure abcd is a parallelogram, ap is perpendicular to dc and cq is perpendicular to ad. if ab=10cm, ad=8cmand ap=8cm then cq=

Draw the frequency polygon representing the following frequency distribution: -

Diff. b/w the outer lateral surface area and inner lateral sur. area of cylindrical metallic pipe 28 cm long is 176 sq. cm.Find the outer and inner radii of the pipe, if the pipe is made 352 cubic cm of metal.

Construct an isosceles triangle whose perimeter is 12 cm and altitude is 4 cm.

If the non parallel sides of trapezium are equal prove that it is cyclic.

in a triangle ABC,E is the midpoint of median AD. Show that area of BED = 1/4 area of ABC

The diagonals of a parallelogram ABCD intersect at point O. Through O, a line is drawn to intersect

AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal areas.

How can we prove this as theorem:

Parallelogram with same base and having equal areas lie between the same parallel.

Please let me know the answer as fast as possible

P and Q are respectively the mid points of side AB and BC of a triangle ABC and R is the mid point of AP show that,

{1} ar(PQR)= 1/2 ar(ARC)

{2} ar (RQC)=3/8 ar(ABC)

3) ar (pBQ) = ar(ARC)

what is the answer of the following question:-

in a parallelogram ABCD, P,Q,R,S are mid- points of the sides AB, CD, DA, and BC respectively. AS, BQ, CR, and DP are joined.Find the ratio of the area of the shaded region to the area of parellogram ABCD.

figure is given Below in picture

Prove that area of a rhombus is half the product of its diagonals.

WHAT IS AREA AXIOMS,CONGRUENT AREA AXIOMS,AREA MONOTONE AXIOM,AREA ADDITION AXIOM AND RECTANGLE AREA AXIOM

Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that

[Hint: From A and C, draw perpendiculars to BD]

D is mid point of side BC of a triangle ABC and E is mid point of BD.If O is mid point of AE , then prove that ar(BOE)=1/8ar(ABC)

The line parallel to the parallel sides of a trapezium passing through the mid-points of the slant sides divide the trapezium into ratio 5:2. Then find the ratio of parallel sides

If E, F, G, H ar respectively the mid points of the sides of a parallelogram ABCD, show that ar(EFGH)= 1/2 ar(ABCD)

Manisha has a garden in the shape of a rhombus. The perimeter of the garden is 40m and one of its diagonal is 16m. She wants to divide it into two equal parts and use these equal parts for growing vegetables and wheat separately. Find the area of each part of the garden.

prove that a cyclic trapezium is always isosceles trapezium.

Prove that the line segment joining the mid-points of opposites sides of a quadrilateral bisect each other.

Please help me with these sums

The given figure shows ΔABC. Points D, E and F are the mid-points of sides AB, AC and BC respectively. Sides AB, BC and CA measure 6 cm, 10 cm and 8 cm respectively.

What is the area of tri DEF

In a parallelogram PQRS, L and M are the mid-points of QR and RS respectively. Prove that :

ar(ΔPLM) = 3/8 ar( IIgm PQRS).

Please help. :)

1 pq=60

2 dcqp&abqp are trapezium

2 ar(dcqp) = 9/11 ar(abqp)

Parallelogram ABCD and rectangle ABEF are on the same base and have equal areas. Show the perimeter of parallelogram is greater than rectangle.

ABC and BDE are two equilateral triangles such that D is the midpoint of BC .AE intersects BC in F.prove that::

P and Qare the mid-points of sides AB and BCof triangle ABC and R is the mid point of AP, show that

i) ar(PQR)=1/2 ar(ARC)

ii) ar(RQC)= 3/8 ar(ABC)

iii) ar(PBQ)=ar(ARC)

If O is the circumcentre of Triangle ABC and OD prependicular to BC. Prove that

Angle BOD = Angle A(a) area of triangle EDC = 2/9 area of triangle ABC

(b) area of triangle FBD = 2/7 area of AFDC

(c) area of triangle DEF = 2/9 area of triangle ABC

(d) area of triangle(EDC + DBF + AFE) = 2 area of triangle DEF

EXPERTS PLS ANSWER AS QUICK AS POSSIBLE WITH THE REASON ALSO.

prove that in a triangle the line segment joining the mid points of any to sides is parallel to the third side.

If a triangle and a parallelogram are on the same base and between the same parallels, then prove that area of the triangle is equal to half the area of the parallelogram.

rnMy teacher is saying that it is a theoram plz tell me by proving it...

Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way thatar ( AOD ) = ar ( BOC ). Prove that ABCD is a trapezium....!!I GuARAnTEeEE ThUMBS uP* FoR De CrrCt aNsaZz... ;)1) ABC is an isosceles triangle with AB=AC. P is any point on BC. perpendiculars PQ and PR are drawn to sides AB and AC respectively. also CS perpendicular to AB. prove that CS=PQ+PR.

2) M and N are midpoints of sides DC and AB respectively of parallelegram ABCD.show that ar(BEC) =ar(MCBN) when it is given that BD parallel to EC.

3) In triangle ABC P and Q are the midpoints of sides AB and AC respectively.R and S are the midpoints of PC and PB respectively.prove that BQ and SR bisect each other.

(1) D and E are points on sides AB and AC respectively of triangle ABC such that ar (DBC) = ar (EBC). Prove that DE//BC

(2) Diagnols AC and BD of a quadrilateral ABCD intersect at O in such a way that ar (AOD) = ar (BOC). Prove that ABCD is a trapezium

(3) Diagnols AC and BD of a quadrilateral ABCD intersect each other at P. Show that ar (APB) x ar (CPD) = ar (APD) x ar (BPC)

CAN SOMEONE PLZZZZ GIVE THE ANSWERS TO THESE QUESTIONS .vryy imp...

1. EXISTENCE POSTULATE

Corresponding to each polygon P lying in a plane, there exists a real number ar(P) $\ge $ 0, called its area.

2. DOMINANCE POSTULATE

For regions ${R}_{1}and{R}_{2}$ in a plane, if ${R}_{1}\subseteq {R}_{2}$, i.e., if ${R}_{1}$ is a part of ${R}_{2}$ then ar(${R}_{1}$) $\le $ ar(${R}_{2}$).

ABCD is a parallelogram.P and Q on BC trisects it.Prove that ar(APQ) =ar(DPQ)=1/6ar(ABCD)

that ar (ABCD)= ar (PBQR)

If each diagonal of a quadrilateral seperates it into two triangles of equal area, prove that the quadrilateral is a parallelogram.

P and Q are any two points lying on the side DC and AD respectively of a parallelogram ABCD.Show that ar(APB)=ar(BQC).....

p is a point in the interior of a parallelogram

abcdshow thatarea apb +area pcd = 1/2 area abcd

area apd +area pbc =area apb+area pcd

If the mid points of the sides of a quadrilateral are joined in order, prove that the are of the parallelogram so formed will be half of the area of the given quadrilateral. Please experts answer it as quickly as possible.

XY is a line parallel to side BC of a triangle ABC. If BEAC and CFAB meet at E and F repectively. Show that ar(ABE) = ar(ACF)

D, E and F are respectively the mid-points of the sides BC, CA and AB of a ΔABC. Show that

(i) BDEF is a parallelogram.

(ii) ar (DEF) = ar (ABC)

(iii) ar (BDEF) = ar (ABC)

Answer :Q. Diagonals AC and BD of a quadrilateral intersect at P. show that-

ar(APB)$\text{\xd7}$ ar(CPD)=ar(APD)$\text{\xd7}$ ar(BPC).

Triangle ABC and DBC are on the same base BC with vertices A and D on opposite sides of BC such that area of triangle ABC = area of triangle DBC. Show that BC bisects AD

O is any point on the diagonal PR of a parallelogram PQRS . prove that ar(PSO) = ar(PQO) .

ABCD is a quadrilateral. A line through D,parallel to AC meets BC produced in P. Prove that area of triangle APD= area of quadrilateral ABCD.

ABCD IS A PARALLELOGRAM, G IS THE POINT ON AB SUCH THAT AG = 2GB, E IS A POINT OF CD SUCH THAT CE = 2DE AND AND F IS A POINT OF BC SUCH THAT BF = 2FC. PROVE THAT

1) ar(ADEG) = ar(GBCE), 2) ar(EGB) = 1/6 ar(ABCD) , 3) ar(EFC) = 1/2 ar(EBF) , 4) ar(EBG) = ar(EFC) , 5) FIND WHAT PORTION OF THE ARE OF PARALLELOGRAM IS THE AREA OF EFG.

A triangle ABCis right angled at A. AL is drawn perpendicular to BC. Prove thatangle BAL =angle ACBABCDE is a pentagon.A line passing through B parallel to AC meets DC produced at F.Show that

ar(ACB)=ar(ACF)

ar(AEDF)=ar(ABCDE)

explain with figure

D, E and F are respectively the mid-points of the sides BC, CA and AB of a ΔABC. Show that

(i) BDEF is a parallelogram.

(ii) ar (DEF) = ar (ABC)

(iii) ar (BDEF) = ar (ABC)

prove that parallelogram on the same base and between the same parallel are equal in area

PSQR is a parallelogram in which angle PSR=125

^{0},angle RQT=?????????In triangle PQR, PS and RT are medians and SM is parallel to RT. Prove that QM= 1/4 PQ.

To show that diagonals of a parallelogram bisect each other.

how to prove it

The circumcentre of the triangle ABC is O. Prove that angle OBC+angle BAC=90 degree. Please answer fast!!!!!!

In triangle ABC, AD is the median and DE || AB. Prove that BE is another median.

Please help! :O

Sorry, i couldn't post the figure.

ABC and ABD are two Triangles on lthe same base AB. If line segment CD is bisected by AB at O, Show that ar(ABC) = ( ABD)

An edge of a cube is increased by 10percent. Find the percentage by which surface area is increased. Please reply fast........

A point E is taken on the side BC of a parallelogram ABCD. AE and DC are produced to meet at F.

Prove that ar( ADF ) = ar (ABFC ).

pqrs is parallelogram where pq is parallel to rs prove that ar of SOR=AR OF PQO

ACCORDING TO ME IN CHAPTER- AREA OF PARALLELOGRAM AND TRIANGLES'S LESSON -2'S EXAMPLE-3

WE FIRST NEED TO PROVE THAT ABCD IS A PARALLELOGRAM..

ABCD is a trapezium with AB parallel to DC. a line parallel to AC intersects AB to X and BC to Y. prove that ar(ADX)=ar(ACY).

excellent videos amazing

got everything inthe mind

thanks meritnation u all r best

The diagonals of quad. ABCD intersect at O .Prove that if BO = OD, then ar (triangle ABC) = ar (triangle ADC).

Pand Q r any 2 points lying on the sides dc and ad respectively of a parallelogram ABCDshow that arAPB=ar BQC

The side AB of a parallelogram ABCD is produced to any point P. A line through A andparallel to CP meets CB produced at Q and then parallelogram PBQR is completed. Show that the area of ABCD = area of PBQR.

I think that the question is wrong, but it came in one of the previous years' question papers.

ar(BPQ)=1/2ar(ABC

i want a report on-compare the performance of two teams for one day cricket match statistically .

(1) performance of both teams to commulative scores.

(2) investigate the interval in which run rate was slow ,fast and average with all the wickets.

(3) compare the performance of individual players

the base of a triangular field is three times its altitude.if the cost of sowing the field at rs 58 per hectare is rs 783,find its base and height.

In trapezium ABCD, AB || DC and L is the mid-point of BC. Through L, a line PQ || AD hasbeen drawn which meets AB in P and DC produced in Q. Prove that ar (ABCD) = ar (APQD)

ABCD is a parallelogram and BC is produced to point Q such that AD=CQ. If AQ intersects DC at P, show that ar(triangle BPC)=ar(triangle DPQ)

ABCD is a rectangle .Prove that ABCD is a square.