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Syllabus

Find the missing frequencies in the following frequency distribution whose mean is 50

X

10

30

50

70

90

Total

F

17

fi

32

F2

19

120

what is the correct formula for adjusted frequency because wile doing the examples on meritnation the formula used was:-

Adjusted frequency= frequency/class size*minimum class size

whereas in the video regarding the histogram where adjusted frequency was used the formula applied there was:-

Adjusted frequency= minimum class size/class size*frequency

what is the formula of mean , median , mode ?

what is class, class size, class interval and class marks????? plz plz plz answer fast......or else i will fail.......plz

In a frequency distribution, the mid-value of a class is 20 and the width of the class is 8.then what is the lower limit ?

a)95

b)25

c)70

d)60

If mean of 5 observations x , x+2 , x+4 , x+6 , x+8 is 11.

Find the median of first three observations.

how to calculate minimum class size?

Plz help,

Find the missing frequencies f1 and f2 in the following frequeny distribution, if it is know that the mean of the distribution is 1.46

xi 0 1 2 345 total

fi 46 fi f2 25 10 5200

The mean of first 8 observations is 18 and last 8 observations is 20 . If the mean of all 15 observations is 19 , find the 8 th observation?

the two consecutive class marks of a distribution are 52 and 57. find the class limits of two intervals

in a continuous frequency distribution class mark of a class is 85 and its lower limit 83 then what will be the upper limit

whats the difference between class interval, class size,class limit,class mark and also ranges,width and length of rectangle ?

Find the median of the given data:

27, 9, 2, 35, 13, 7, 40, 20, 28, 22, 25, 24

Find the value of p, if the mean of the following distribution is 20

x: 15 17 19 20+p 23

f: 2 3 4 5p 6

note : the method should be of sigma fixi.

Q1. In a family of seven persons there are three earning members having monthly income of Rs. 1800, Rs. 1400 and Rs. 1000. What is the average income of a member in a family?

Q2. The mean weight of 34 students of class 9th of a school is 42kg. If the weight of the teacher be included, the mean rises by 400gm. Find the weight of teacher.

Q3. the mean of six no. is 20. If one no. is excluded, the mean is 15. Find the value of the excluded no.

how too find class marks ??explain with an example ??

wat is histogram , expalin with an example !?expain who to find scale with example !???In a morning walk, I had 20 rounds of a park. During this period I came across person A, person B, person C and person D, 11 times, 7 times, 10 times and 5 times respectively. I want to represent this data graphically, which of the following is the best representation ?

Differentiate between class limits and true class limits.Give examples

For a particular year following is the distribution of ages (in years) of primary school teachers in a district

Age (in years)

15-20

20-25

25-30

30-35

35-40

40-45

45-50

No. of teachers

10

30

50

50

30

6

4

1) 1) Write the lower limit of first class interval

2) 2) Determine the class limits of the fourth class interval

3) 3) Find the class mark of the class 45-50

4) Determine the class-size

what is the exact formula for ADJUSTED FREQUENCY??????????????

BECAUSE 2 VIDEOS OF THE SAME CHAPTER BUT OF OTHER LESSON SHOW DIFFERENT FORMULA SO WHICH ONE IS CORRECT.

Class size = Difference between class marks of two consecutive classes.= 52 - 47 = 5

Lower-class limit = class marks - 1/2 of class size= 47+2.5 = 49.5

Upper class limit = class marks + 1/2 of class size = 52+2.5 = 54.5

Since, the class-limits form a continuous frequency distribution; the true class limits and the class-limits are the

same

marks:number of students

100-150:60, 150-200:100, 200-300:100, 300-500:80, 500-800:180

draw a histogram

how to make class intervals continuous?

Write the equation y root 3= 8x+root 3 in the form ax+by+c=0. Check weather (0,-1) and (root 3, 9) are the solution of this equation.

use of statistics in our daily life

what is adjusted frequency ? why is it used ? please explain in detail.

the mean of 20 observation is 25 . if each observation is multiplied by 2 , then find the mean of new observations .

Help,

The mean of 25 observatios is 36. Out of thes,if the mean of first 13 observation is 32 and that of last 13 observation is 40,find the 13th observation.

153, 140, 148, 150, 154, 142, 146, 147.

Pls do not give any links.

the mean of 15 numbers is 27 .if each number is multiplied by 4,what will be the mean of the new number

Mean of 50 observations was found to be 80.4. But later on it was discovered that 96 was misread as 69 at one place. Find the correct mean. If to each observation a constant value k is added, how is the mean affected?

find the mean median of first 12 odd composite numbers

Please do answer today only...coz it's my exam tomm..plzz..

Thanks is u do ... :)

17,2,7,27,15,5,14,8,10,24,

48,10,8,7,18,28

if the ratio of mean and median of a certain data is 2:3 , then find the ratio of its mode and mean.

Q. Find the mean and medium of the following numbers:

155, 160, 145, 149, 150, 147, 152, 144, 148.

The following observation have been arranged in ascending order. if the median of the data is 63, find the value of x

29,32,48,50,x,x+2,72,84,95

how to find minimum class size?

design a crossword puzzle using mathematical terms

the class marks of distribution are

47,52,57,62,67,72,77,82 determine the class size,class limit,ture class limits.

the ratio between upper limit and lower limit of a class is 3:2. if the class mark is 15 , then find lower limit of the class-interval.the mean of five numbers is 30. if one number is excluded, their mean becomes 28. the excluded number is:

the mean of 10 observations is 42 . if each observations is decreased by 12 find the new mean

Find the mean of factors of 24

Xi 0 1 2 3 4 5

Xf 3 3 p 7 p-1 4

In a frequency distribution,mid value of a class is 10 and width of class is 6. The lower limit of the class isthe mean of 16 numbers is 8. If 2 is added to every number, what will be the new mean ?

^{th}observations.If x is the number of hours a labourer is on work "and y is his wages in rupees then y=4x+3. Draw the work wages graph of this equation . From the graph , Find the wages of a labourer Who puts in 4 hours of work.

Calculate the mode of each using the empirical formula. 17, 10, 12, 11, 10, 15, 14, 11, 12, 13

the class mark of a distribution are :

37,42,47,52,57

determine the class size and class limits......

21. In the following groups of data, tell whether the mean or the median best describes the data:

(i) 6, 4, 2, 12, 2 (ii) 31, 28, 24, 9, 23 (iii) 45, 51, 47, 65, 36 (iv) 10, 20, 30, 100, 9

the mean of 5 number is 18 if one number is excluded, their mean is 16 .find the excluded number

how to convert the dis-continuous class into continuous class interval

141 123 92 85 214 91 94 128 114 120 90 117 121 151

146 133 100 88 100 125 120 108 116 109 117 94 86 196

92 110 119 138 125 117 125 129 103 197 149 139 140 78

205 133 135 121 102 96 80 136

Form the grouped frequency table by dividing the variable range into intervals of equal width of 20 gsm such that the mid value of the first interval is 80 gms.

Find the value of x and y in following distribution if it known that the mean of the distribution is 1.46

No. of students 0 1 2 3 4 5 Total

Frequency 46 x y 25 10 5 200

62 , 65 , 68 , 70 , 72 , 74 , 76 , 78 , 80 , 82 , 96 , 101,

find

a) the median,

b) the first quartile,

c) the third quartile,

d) the interquartile range (IQR).

the mean of 5 numbers is 7 if one more number is included the mean increases by 2. find the number included

if the mean of the observations x, x+3 ,x+5 ,x+7, and x+10 is 9. what is the mean of last three observations.

IS THERE ANY FORMULA TO CALCULATE LOWER CLASS LIMITS OF LOWER CLASS,UPPER CLASS LIMIT OF UPPER CLASS , LOWEST CLASS LIMIT UPEER CLASS LIMIT CLASS INTERVALS CLASS SIZE MID VALUEIF ANY OF THE TWO THINGS ARE GIVEN FROM THE ASKED ABOVE.

10 observations 6, 14, 15, 7, x+1, 2x-13, 30, 32, 34, 43 are written in ascending order. The median of the data is 24. Find the value of x.

The mean weight of 8 numbers is 15, if each number is multiplied by 2, what will be the new mean

The mean of 12 numbers is 40. if each number is divided by 8 what will be the mean of the new number

age group 10-14 15-19 20-24 25-29 30-34

no. of females 300 980 800 580 290

draw histogram and frequency polygon on the same graph

mean of 50 obs. was found to be 80.4 but later on it was found that 96 was misread as 69 at one place . find the correct mean

1. Marks secured by a group of 10 students are as follows:

16, 18, 29, 31, 20, 23, 26, 25, 32, 20

i) Find the mean of the data.

ii) If 32 is replaced by 23 in the data, find the new mean.

iii) If each observation in the given data is increased by 5 marks, the what will be the mean?

iv) If two students securing 16 and 32 marks leaves the group, then find the mean of remaining 8 students.

how to find the class size and class interval when the class marks are given.pls tell fast....

The means of two groups of 15 and 20 observations are 20 and 25 respectively. Find the mean of all the 35 observations.

The mean of 20 numbers is 18. If 3 is added to each of the first ten numbers, find the mean of the new set of 20 numbers.

Give one example of a SITUATION where:

i. mean is an appropriate measure of central tendency.

ii. median is an appropriate measure of central tendency but mean is not.

find the mean of the following data by shortcut method

the mean salary paid to 1000 workers of a factory was found to be Rs. 180.40 later it was discovered to the wages of two workers wrongly taken as Rs. 297 and Rs. 165 instead of Rs. 197 and Rs. 185 find the correct mean

what is the mean of first five natural numbers

marks obtained (out of 60 ) | No. of students

5 | 7

15 | 10

20 | 6

35 | 8

40 | 12

45 | 3

50 | 5

60 | 4

The mean 20 observation is 25. In each observation is multiplied by 2. What is the new mean of Observation?????/

(i) He scores more than 80% marks.

(ii) He scores less than 60%marks.

(iii) He scores more than or equal to 40 but less than 80

Class Interval Less than 40 40 - 60 60 - 80 80 -100

Frequency 610 840 750

The mean of 200 items was 50. Later on it was discovered that 2 items were misread as 92 and 8 instead of 192 and 88. Find the correct mean.