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can any1 tell a+b+ c whole CUBE

what is the simplest rationalization factor of root 5 and why?kindly explain .

crossword puzzles with mathematical terms with answers

prove that root 5 is an irrartional number using theory method!!!!

quick!!!!

what is the value of (343) -1/3

if both x-2 and x-1/

_{2}are factors of px^{2}+5x+r show that p=r^{2}-(a^{2}+1)x+a, and verify the relationship between the zeroes and the coefficients.Factorise : x

^{3 }- 6x^{2}+ 11x -6 using FACTOR THEOREM.what is the formula of (a+b+c) whole cube

if x -1/x =3; then find the value of x

^{3}-1/x^{3}^{2}- 15x - 34Give me a list of all the algebraic identities? Also the conditional identity.

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find the integral zero of

4x^3=20x^2-X-5

1 )If a + b + c = 0 ( a

^{2 }/ bc ) + ( b^{2}/ ca ) + ( c^{2 }/ ab^{ }) = 32 ) Find the value of a ) 55

^{3 }- 25^{3 }- 30^{3 }b ) 99

^{3}^{-1}/x^{-1}+y^{-1})+ (x^{-1}/x^{-1}-y^{-1})=2y^{2}/y^{2}-x^{2}If a+b+c=6 and ab+bc+ca=11, find the value of a

^{3}+b^{3}+c^{3}-3abc.using factor theorem, find the value of 'a', if 2x

^{4}-ax^{3}+4x^{2}-x+2 is divisible by 2x+1^{4}-2x^{3}+3x^{2}-ax+b when divided by (x-1) and (x+1) leaves the remainders 5 and 19 respectively.find the values of a and b.hence,find the remainder when f(x) is divided by (x-2).if x

^{4}+ 1/x^{4}= 47, then find the value of x^{3 }+ 1/x^{3}If (x+a) is a factor of two polynomials x2+px+q and x2+mx+n, then prove that :

a=n- q/m-pfactorise:

x

^{3}+13x^{2}+32x+20 (by remainder theorem)How do we prove geometrically a

^{2-}b^{2 }= (a-b)(a+b)Find the value of a for which (x+a) is a factor of the polynomial f(x)= x

^{3}+ax^{2}-2x+a+6If x

^{2 }+ 1/x^{2}=7 then find value of x^{3 }+ 1/x^{3}If x= 9+4 (root 5) then find (root x) - 1/ (root x)

PLeaseee answer fasst! needed at the moment! :)

(3Ycube-3/2ysquare+Ky+5) is exaxtly divisible by (Y-1/2) . show the calculation

If a

^{2}+ b^{2}+ c^{2}ab - bc - ca = 0 , prove that a=b=c .^{2}+b^{2}+c^{2}=6, a^{3}+b^{3}+c^{3}=8, then a^{4}+b^{4}+c^{4}is?Find the value of x

^{3}+y^{3}- 12xy + 64 when x + y = - 4The remainder when 4x3 - 3x2 + 2x - 4 is divided by x+1/2 is -

if x= 2+root3 then find the value of x

^{2}+ 1/x^{2}pl.. need the answer really fast................

Factorise x

^{3}+ y^{3}value of p if x+1/2 is a factor of px raised to 2 - 4px + 3

Factorise : x ( cube ) + y ( cube ) + z ( cube ) - 3xyz.

tell me fast friend's...

^{2 }the coefficient of x^{2}is :factorise

^{x4 +x2 +1 }Simplify:(x^{p}/x^{q})^{p+q}. (x^{q}/x^{r})^{q+r }. (x^{r}/x^{p})^{r+p}Factorise :a

^{3}(b-c)^{3}+ b^{3}(c-a)^{3 }+c^{3}(a-b)^{3}Factorise x

^{3}- 23x^{2}+ 142x - 120if sum of remainders obtained by dividing ax

^{3-}3ax^{2}+7x+5 by (x+1) and (x+2) is (-36) then find 'a'plz answer this one

"If a+b+c = 0

Then a

^{3}+b^{3}+c^{3}= 3abc"Now what if a+b+c is

tonot equal, then how do you solve0?a^{3}+b+^{3}+c^{3}Solve this-

12^{3}+14^{3}+2^{3}.(a) 5 terms (b) 3 terms

(c) 4 terms (d) 1 term

what is the whole cube of (x+y+z)

^{3}+kx^{2}+2x+8. Find k.find the value of a and b, so that the polynomial (x

^{3}+10x^{2}+ax +b) is exactly by (x-1) as well as (x-2)y square + root 2 is a polynomial with 1 variable and 3 root "t" +"t' root 2 is a not a polynomial . can u plzzzz explain

factorise: (x-y)

^{3}+(y-z)^{3}+(z-x)^{3}how to prove the identiy

a

^{3}+b^{3}+c^{3}-3abcif a+b+c=0 then, a cube + b cube + c cube

Using factor theorem, show that x-y, y-z, z-x are the factors of x

^{2}(y-z)+y^{2}(z-x)+z^{2}(x-y)Without actual division, prove that 2x

^{4}-5x^{3}-2x2 -x+2 is exactly divisible by x^{2}-3x+2what is nonnegative integral power

may i pls get the ans :

1. find x if 2

^{x-5X}5^{x-4}=52.factorise : 6x

^{2}+5x-63.factorise : x

^{3}-3x^{2}-9x-54.x=2+root3 , find x

^{2}+1/x^{2}^{5. find the value of a and b 5+2root3/7+4root3=a+broot3}(l+m)³ + (2m+3n)³ + (3n+4l)³ - 3(l+m)(2m+3n)(3n+4l)

verify x3+y3=(x+y)(x2-xy+y2)

Simplify : (3/5)

^{4}*(8/5)^{12}*(32/5)^{6}simplify (2x-y+z)^2-(2x+y-z)^2

experts pls answer as fast as possible

Factorise:

x

^{2}+1/x^{2}+2-2x-2/xsimplify The following:

4th root of 12 * 7th root of 6

f (x )

If x+(1/x)=5, then evaluate x

^{6}+(1/x^{6})a2+2ab+b

^{2}-9c^{2}x

^{3}+y^{3}+z^{3}-3xyz = 1/2 (x+y+z)[(x-y)^{2}+(y-z)^{2}+(z-x)^{2}](ii) a^3 ? 64b^3 ? 27c^3 ? 36abc

If a

^{1/3}+ b^{1/3}+ c^{1/3}= 0 thena) a+b+c=0

b) (a+b+c)

^{3}=27abcc) a+b+c=3abc

d) a

^{3}+b^{3}+c^{3}=0Also explain how ??

Find the following of zero of the polynomial x

^{3}+ 3x^{2}-3x-1Find the remainder when

x^{3}+ 3x^{2}+ 3x+ 1 is divided by(i)

x+ 1 (ii) (iii)x(iv)

x+ π (v) 5 + 2xThe polynomial p(x) =3x

^{2}-5x+k and q(x) =2x^{3}-6x^{2}+5k-3 when divided by the polynomial x-2 leave the remainders r_{1}and r_{2}. Find the value of k if r_{1}-r_{2}=0.give the property

if a+b+c =5 and ab+bc+ca=10, then prove that a

^{3}+b^{3}+c^{3}-3abc= -25.Can you factorize this expression please, x

^{12 }- y^{12}= ?^{3}+ bx^{2}+ x + 2/3 if x+3 is a factor of f(x) and if f(x) is divided by x+2 then we get remainder as 5 then find the value of a and bsimplify: 1/ ( root3 + root2 - root5)

factorise it. x4 + x2 + 25

^{2}-6y-k, find the value of k. Also find the other zero.If a+b = 10 and a

^{2}+ b^{2 }= 58 find the value of a^{3}+ b^{3}The polynomial p(x)=x^{3 }+ ax^{2 }+ bx - 20 when divided by (x-5) and (x-3) leaves the remainder 0 and -2 respectively. Find the values of a and b .if ax

^{3}+bx^{2}+x-6 has x+2 as factor and leaves the remainder 4 when divided by (x-2), find the values of 'a' and 'b' .One of the factors of (9x

^{2}-1)-(1+3x)^{2 }is(a)3+x (b)3-x (c)3x-1 (d)3x+1

Q- if x square + 1/ x square = 83 then find the value of x cube - 1/ x cube

The maximum number of zeroes of the polynomial p(y) = my

^{a }is :(a) a+1 (b) m (c) m+1 (d) a

(i) if both x-2 and x-1/2 are factors of px

^{2}+5x + r , show that p=r(ii)if the polynomial az

^{3}+4z^{2}+3z-4 and z^{3}-4z+a leave the same remainder when divided by z-3 find 'a'^{3}- 9x^{2 }+ 45x - 63 is divided by x + 2....If(X

^{2}-1) is a factor of ax^{4}+bx^{3}+cx^{2}+dx+e,show that a+c+e=b+d=0Prove that

ais always non-negative for all valuesof a, b and c.^{2}+b^{2}+c^{2}-ab-bc-ca