General Science Solutions Solutions for Class 8 Science Chapter 6 Composition Of Matter are provided here with simple step-by-step explanations. These solutions for Composition Of Matter are extremely popular among class 8 students for Science Composition Of Matter Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the General Science Solutions Book of class 8 Science Chapter 6 are provided here for you for free. You will also love the ad-free experience on Meritnation’s General Science Solutions Solutions. All General Science Solutions Solutions for class 8 Science are prepared by experts and are 100% accurate.
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Question 1:
Choose the appropriate option and rewrite the following statements.
A. The intermolecular force is _______ in the paricles of solid.
i. Minimum ii. Moderate iii.maximum iv.indefinite.
B. Solids retain their voume even when external pressure is applied. This property is called__________
i. plasticity ii. Incompressibility iii. fluidity iv. elasticity
C. Matter is classified into the types mixture, compound and element by applying the criterion______________
i. states of matter ii Phases of matters iii chemical compositions of matter iv all of these
D. Matter that contain two or more constituent substances is called__________
i. mixture ii. compound iii. element iv. metalloid
E. Milk is an example of type of matter called __________
i. solution ii. homogeneous mixture iii heterogeneous mixture iv. suspension
F. Water, mercury and bromine are similar o each other, because three are
i. liquids ii. compounds iii. nonmetals iv. elements.
G. valency of carbon is 4 and that of oxygen is 2. From this, we understand that there are _______ chemical bond/bonds between the carbon atom and one oxygen atom in the compound-carbon dioxide.
i. 1 ii. 2 iii. 3 iv. 4
Answer:
A. The intermolecular force is maximum in the paricles of solid.
i. Minimum ii. Moderate iii.maximum iv.indefinite.
B. Solids retain their voume even when external pressure is applied. This property is called incompressibility.
i. plasticity ii. Incompressibility iii. fluidity iv. elasticity
C. Matter is classified into the types mixture, compound and element by applying the criterion states of matter.
i. states of matter ii Phases of matters iii chemical compositions of matter iv all of these
D. Matter that contain two or more constituent substances is called compound.
i. mixture ii. compound iii. element iv. metalloid
E. Milk is an example of type of matter called homogeneous mixture.
i. solution ii. homogeneous mixture iii heterogeneous mixture iv. suspension
F. Water, mercury and bromine are similar to each other, because three are liquids.
i. liquids ii. compounds iii. nonmetals iv. elements.
G. valency of carbon is 4 and that of oxygen is 2. From this, we understand that there are 2 chemical bond/bonds between the carbon atom and one oxygen atom in the compound carbon dioxide.
i. 1 ii. 2 iii. 3 iv. 4
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Question 2:
Identify the odd term out and explain
A. Gold, silver, copper, brass
B.Hydrogen, hydrogen peroxide, carbon dioxide, water vapour.
C.Milk, lemon juice, carbon, steel.
D.water, mercury, bromine, petrol.
E.sugar, slat, baking soda, blue vitrol.
F.Hydrogen, sodium, potassium, carbon.
Answer:
a.Brass is odd one out because it is an alloy and gold, silver, copper are element.
b.Hydrogen is odd one out because it is an element and others are compound.
c.Carbon is odd one out because it is an element and others are mixture of various elements.
d.Water is odd one out because it is universal solvent and rest are not universal solvent.
e.Baking soda is odd one out because it is a mixture of various elements and others are compound.
f.Carbon is odd one out because it has 4 valence electrons and others have 1 valence electron.
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Question 3:
Answer the following questions.
A.Plants synthesize glucose in sunlight with the help of chlorophyll from carbon dioxide and water and give away oxygen. identify the four compounds in this process and name their types.
B. In one sample of brass, the following ingredients were found : copper (70%) and zinc (30%). Identify the solvent, solute and solution from these.
C. Sea water tastes salty due to the dissolved salt. the salinity (the proportion of salts in water) of some water bodies Lonar lake - 7.9 %, Pacific Ocean 3.5%, Mediterranean sea- 3.8%, Dead sea- 33.7%. Explain two characteristics of mixture from the above information.
Answer:
a.Photosynthesis is a chemical process through which plants, some bacteria and algae, produce glucose and oxygen from carbon dioxide and water, using only light as a source of energy, which is absorbed by chlorophyll.
Four substances in this process are as follows:
1.Carbon dioxide = organic compound
2.Water = organic compound
3.Glucose = organic compound
4.Chlorophyll = organo-metallic compound or complex compound
b.Brass is an alloy made primarily of copper, usually with zinc.Brass as a solid solution consisting of zinc and other metals as solute dissolved in copper taken as solvent. So that, the brass meets all the criteria of a solution.
c.Characteristics of mixtures from above information are:
1.Constituent substances of a mixture are two or more elements or compounds.
2.The proportion of constituent substances in a mixture can be variable.
3.The properties of constituent substances are retained in the mixture.
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Question 4:
Give two examples each
A. Liquid element
B. Gaseous element
C. Solid element
D.Homogeneous mixture
E.Colloid
F.Organic compound
G.Complex compound
H.Inorganic compound
I.Metalloid
J.Element with valency 1
K.Element with valency 2
Answer:
a.Liquid element = mercury, bromine
b.Gaseous element = oxygen, nitrogen, hydrogen
c.Solid element = sodium, carbon, aluminium
d.Homogeneous mixture = sugar in water, corn oil, blood plasma
e.Colloid = mayonnaise, milk, butter, gelatin, jelly, muddy water
f.Organic compound = proteins, glucose, urea, carbohydrates
g.Complex compound = chlorophyll, hemoglobin, cyanocobalamine
h.Inorganic compound = limestone, rust, common salt
i.Metalloid = silicon, germanium
j.Element with valency 1 = sodium, potassium, chlorine
k.Element with valency 2 = magnesium, calcium
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Question 5:
Write the names and symbols of the constituent eleements and identify their valencies from the molecular formulae given below.
KCl, HBr, MgBr2, K2O, NaH, CaCl2, CCl4, HI, H2S, Na2S, FeS, BaCl2
Answer:
| Compounds | Name of compounds | Symbol of constituent elements | Valency of constituent elements |
| KCl | Potassium chloride | K, Cl | K = 1, Cl = 1 |
| HBr | Hydrogen bromide | K, Br | K = 1, Br = 1 |
| MgBr2 | Magnesium bromide | Mg, Br | Mg = 2, Br = 1 |
| K2O | Potassium oxide | K, O | K = 1, O = 2 |
| NaH | Sodium hydride | Na, H | Na = 1, H = 1 |
| CaCl2 | Calcium chloride | Ca, Cl | Ca = 2, Cl = 1 |
| CCl4 | Carbon tetrachloride | C, Cl | C = 4, Cl = 1 |
| HI | Hydrogen iodide | H, I | H = 1, I = 1 |
| H2S | Hydrogen sulphide | H, S | H = 1, S = 2 |
| Na2S | Sodium sulphide | Na, S | Na = 1, S = 2 |
| FeS | Iron (II) Sulfide | Fe, S | F = 2, S = 2 |
| BaCl2 | Barium chloride | Ba, Cl | B = 2, Cl = 1 |
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Question 6:
Chemical composition of some matter is given in the following table. Identify the main type of matter from their.
| Name of matter | Chemical composition | Main type of matter |
| Sea water | ||
| Distilled water | ||
| Hydrogen gas filled in a ballon | ||
| The gas in LPG cylinder | ||
| Baking soda | ||
| Pure gold | ||
| The gas in oxygen cylinder | O2 | |
| Bronze | Cu + Sn | |
| Diamond | C | |
| Heated white powder of blue vitroi | CuSO4 | |
| Lime stone | CaCO3 | |
| Dilute hydrochloric acid | HCL+ H2O |
Answer:
|
Name of matter |
Chemical composition | Main type of matter |
| Sea water | mixture | |
| Distilled water | compound | |
| Hydrogen gas filled in a ballon | element(molecule) | |
| The gas in LPG cylinder | mixture | |
| Baking soda | mixture | |
| Pure gold | element | |
| The gas in oxygen cylinder | element(molecule) | |
| Bronze | Cu + Sn | mixture |
| Diamond | element(allotrope) | |
| Heated white powder of blue vitroi | compound | |
| Lime stone | compound | |
| Dilute hydrochloric acid | compound |
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Question 7:
Write scientific reason.
A. Hydrogen is combustible, oxygen helps combustion, but water helps to extinguish fire.
B. Constituent substances of a colloid cannot be separated by ordinary filtration.
C. Lemon sherbat has sweet, sour and salty taste and it can be poured in a glass.
D. A solid matter has the properties of definite shape and volume.
Answer:
a.Water is made up of two elements, that's hydrogen and oxygen. Hydrogen is flammable, but oxygen is not. Flammability is the ability of a combustible material with an adequate supply of oxygen (or another oxidiser) to sustain enough heat energy to keep a fire going after it has been ignited. Though water is made up of two atoms of hydrogen and one atom of oxygen by forming an ionic compound, it does not possess the characteristics of them because a compound does not have the properties of its constituent elements. Therefore, water has its own properties, which helps to extinguish fire.
b.Constituent substances of a colloid cannot be separated by ordinary filtration because the size of the particles in a colloids(or colloidal solution) is bigger than those in a true solution but smaller than those in suspension.It is in between 1nm to 100nm in diameter. The size of ordinary filter paper is more than 100nm due to which colloidal particles are passed through the pores of a filter paper. Due to which, we prefer to use ultrafilter paper so that, filteration of colloidal particles take place easily.
c.Lemon sherbat has sweet, sour and salty taste and it can be poured in a glass because sour taste indicates presence of an acid and if acid is poured in a vessel made up of metal, then acid reacts with metal and makes it poisonous in nature.So we prefer to take vessel made up of glass material.
d.A solid matter has the properties of definite shape and volume because of the following reasons:
1)Intermolecular force of attraction between the particles of matter is very strong.
2)Internuclear space between the particles of matter is negligible.
3)Particles of matter are very close to each other that they only vibrate at their fixed position.
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Question 8:
Deduce the molecular formulae of the compound obtained from the following pairs of elements by the cross multiplication method.
A. C (Valency 4) & Cl (Valency 1)
B. N (Valency 3) & H (Valency 1)
C. C (Valency 4) & O (Valency 2)
D. Ca (Valency 2) & O (Valency 2)
Answer:
a. C (Valency 4) & Cl (Valency 1) :
Step 1 : Write the symbols of the radicals.
C Cl
Step 2 : Write the valency below the respective radical.
C Cl
4 1
Step 3 : Cross-multiply symbols of radicals with their respective valency.
Step 4 : Write down the chemical formula of the compound.
CCl4
b. N (Valency 3) & H (Valency 1)
Step 1 : Write the symbols of the radicals.
N H
Step 2 : Write the valency below the respective radical.
N H
3 1
Step 3 : Cross-multiply symbols of radicals with their respective valency.
Step 4 : Write down the chemical formula of the compound.
NH3
C. C (Valency 4) & O (Valency 2)
Step 1 : Write the symbols of the radicals.
C O
Step 2 : Write the valency below the respective radical.
C O
4 2
Step 3 : Cross-multiply symbols of radicals with their respective valency.
Step 4 : Write down the chemical formula of the compound.
CO2
D. Ca (Valency 2) & O (Valency 2)
Step 1 : Write the symbols of the radicals.
Ca O
Step 2 : Write the valency below the respective radical.
Ca O
2 2
Step 3 : Cross-multiply symbols of radicals with their respective valency.
Step 4 : Write down the chemical formula of the compound.
CaO
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