NCERT Solutions
Board Paper Solutions
Ask & Answer
School Talk
Login
GET APP
Login
Create Account
Popular
Latest
Expert Answers
ALL
Shreyans Singh
Subject: Maths
, asked on 23/9/17
Q. If 4th, 7th, 10th terms of a G.P. are p,q,r respectively then
(A)
${p}^{2}={q}^{2}+{r}^{2}$
(B)
${q}^{2}=pr$
(C)
${p}^{2}=qr$
(D)
$pqr+pq+1=0$
Answer
1
Ranjan Shivam
Subject: Maths
, asked on 22/9/17
solve it
Q. Find
(i)
$\sum _{r=0}^{9}\frac{{r}^{2}}{{r}^{2}+{\left(9-r\right)}^{2}}$
Answer
2
Shubhrajyoti Ghosh
Subject: Maths
, asked on 21/9/17
Dear expert
, why the above sum is done so elaborately?? Why is it not done in short as follows:
a
=1,
l
=11
Therefore,
S
_{n}
=n
/2(
a+l
)
or, 36=
n
/2(1+11)
or, 36=(
n
/2)*12
or, 36=6
n
or, n=6
Answer
1
Royel Ghost
Subject: Maths
, asked on 19/9/17
EXAMPLE 16. Show that there is no A.P. which consists of only distinct prime numbers.
EXAMPLE 17. Show that in an A.P. the sum of the terms equidistant from the beginning and end is always same and equal to the sum of first and last terms.
Answer
1
Siddharth Bothra
Subject: Maths
, asked on 17/9/17
Q). If the
${6}^{th}and{16}^{th}$
term of a G.P. are x - y and
${x}^{2}+xy+{y}^{2}$
respectively, then what is the
${11}^{th}$
term of this G.P?
Answer
2
Siddharth Bothra
Subject: Maths
, asked on 17/9/17
Plz give the answer
Answer
1
Yashaswi Agrawal
Subject: Maths
, asked on 16/9/17
1 + (2 + 3) + (4 + 5 + 6)... up to n terms. Find the sum of the nth bracket.
Answer
5
Shivam Desale
Subject: Maths
, asked on 15/9/17
Qn. No. 29:
29. If the m
^{th}
term ofa H.P be n and n
^{th }
term be m, then the r
^{th}
term will be.
$\left(A\right)\frac{r}{mn}\left(B\right)\frac{mn}{r+1}\left(C\right)\frac{mn}{r}\left(D\right)\frac{mn}{r-1}$
Answer
1
Shubhrajyoti Ghosh
Subject: Maths
, asked on 13/9/17
The n
^{th}
term of a sequence is equal to half of the sum of its first (
n
– 1) terms. If
T
_{1}
= 10, then what is the value of
T
_{9}
?
(A)
$\frac{10.935}{16}$
(B)
$\frac{10.935}{32}$
(C)
$\frac{10.935}{64}$
(D)
$\frac{10.935}{128}$
Answer
1
Soumyadeep Kar
Subject: Maths
, asked on 12/9/17
45th question
Answer
2
Soumyadeep Kar
Subject: Maths
, asked on 10/9/17
38th question
Q.38. If
$S=\sum _{n=1}^{99}\frac{{5}^{100}}{{\left(25\right)}^{n}+{5}^{100}}$
(A) S = 49.5
(B) S = 50
(C) S = 49
(D) S = 50.5
Answer
2
Ashutosh Kumar
Subject: Maths
, asked on 4/9/17
Please solve Q.no.25 of ex-9.3 by any other method.The ncert solution given by meritnation of this question is too lengthy and sometimes confusing thats why please solve this question by any other short method.
Answer
1
Amitesh Kumar
Subject: Maths
, asked on 1/9/17
5 distinct 2 digit no. are in G.P find the middle term?
Answer
1
Soumyadeep Kar
Subject: Maths
, asked on 29/8/17
5. If
$\frac{1}{{1}^{4}}+\frac{1}{{2}^{4}}+\frac{1}{{3}^{4}}+...+\infty =\frac{{\pi}^{4}}{90}$
, then the value of
$\frac{1}{{1}^{4}}+\frac{1}{{3}^{4}}+\frac{1}{{5}^{4}}+...+\infty $
is
Answer
3
Arunav Goel
Subject: Maths
, asked on 23/8/17
If n
^{th}
term of the series 25+29+33+.... and 3+4+6+9+.... are equal, then find n.
Answer
1
Prev
7
8
9
10
11
Next
What are you looking for?

(A) ${p}^{2}={q}^{2}+{r}^{2}$ (B) ${q}^{2}=pr$ (C) ${p}^{2}=qr$ (D) $pqr+pq+1=0$

Q. Find

(i) $\sum _{r=0}^{9}\frac{{r}^{2}}{{r}^{2}+{\left(9-r\right)}^{2}}$

Dear expert, why the above sum is done so elaborately?? Why is it not done in short as follows:a=1,l=11Therefore,

S/2(_{n}=na+l)or, 36=

n/2(1+11)or, 36=(

n/2)*12or, 36=6

nor, n=6

EXAMPLE 17. Show that in an A.P. the sum of the terms equidistant from the beginning and end is always same and equal to the sum of first and last terms.

29. If the m

^{th}term ofa H.P be n and n^{th }term be m, then the r^{th}term will be.$\left(A\right)\frac{r}{mn}\left(B\right)\frac{mn}{r+1}\left(C\right)\frac{mn}{r}\left(D\right)\frac{mn}{r-1}$

^{th}term of a sequence is equal to half of the sum of its first (n– 1) terms. IfT_{1}= 10, then what is the value ofT_{9}?(A) $\frac{10.935}{16}$ (B) $\frac{10.935}{32}$ (C) $\frac{10.935}{64}$ (D) $\frac{10.935}{128}$

Q.38. If $S=\sum _{n=1}^{99}\frac{{5}^{100}}{{\left(25\right)}^{n}+{5}^{100}}$

(A) S = 49.5

(B) S = 50

(C) S = 49

(D) S = 50.5

^{th}term of the series 25+29+33+.... and 3+4+6+9+.... are equal, then find n.