1/3x- 1/7y=2/3 1/2x-1/3y=1/6 solve by reduction method Share with your friends Share 0 Varun.Rawat answered this The given system of equations is :13x - 17y = 23 .....112x - 13y = 16 ....2Put 1x = u and 1y = vNow, the above system of equations becomes : u3 - v7 = 23⇒7u - 3v = 14 .....3u2 - v3 = 16⇒3u-2v = 1 ......4Multiply 3 by 2 and 4 by 3, we get14u - 6v = 28 ......59u - 6v = 3 .....6Subtracting 6 from 5, we get5u = 25 ⇒ u = 5Put u = 5 in 3, we get35 - 3v = 14⇒-3v = -21 ⇒ v = 7Now, x = 1u = 15 and y = 1v = 17 2 View Full Answer Meenakshi answered this 1/3x - 1/7y = 2/3 LCM=21 7x-3y/21 = 2/3 7x-3y = 2/3 *21 ( * = multiplication ) 7x-3y = 14 similarly by using LCM for the second equation you will get : 3x - 2y = 1 (7x-3y=14) * 2 (3x-2y=1) * 3 14x-6y=28 9x-6y=3 When you subtract the two equations you will get 5x = 25 x=25/5 x=5 substitute x in any equation 3x-2y = 1 (3*5) - 2y = 1 15-2y = 1 -2y = 1-15 y = -14/-2 y = 7 1
