10g of a sample of conc HCl was diluted with water and the solution was added to - Science - Chemical Reactions and Equations

Question

10g of a sample of conc HCl was diluted with water and the solution
was added to a piece of CaCO3 weighing 7g After
completion of the reaction, 2 8 g of marble remained unreacted What
was the percentage strength of the conc acid?

Geetha · Accepted Answer

CaCO3 + 2HCl →CaCl2 + H2O + CO2100 g of CaCO3 reacts with 2 × 36
5 = 73 g of HClIts given 2
8 g of marble remains unreacted
 That means all HCl is consumed and is the limiting reagentThe amount of marble reacted = 7 -2
8 = 4
2 gThe amount of HCl needed for 4
2 g of CaCO3 = 73100×4 2=3
066 gThe % strength = 3
06610 × 100 = 30 66 %

10g of a sample of conc. HCl was diluted with water and the solution was added to a piece of CaCO3 weighing 7g. After completion of the reaction, 2.8 g of marble remained unreacted. What was the percentage strength of the conc. acid?

10g of a sample of conc. HCl was diluted with water and the solution was added to a piece of CaCO₃ weighing 7g. After completion of the reaction, 2.8 g of marble remained unreacted. What was the percentage strength of the conc. acid?