2 tangents QA and QB are drawn to the circle wit centre O such that <AQB = 60 with AQ = 3 cm, find OQ

pls help



We know that, tangents drawn from an external point to a circle are equal in lengths.So, QA = QB    ......1We know that, tangent to the circle is always  to the radius at the point of contact.So, OAQ = OBQ = 90°     .......2In OAQ and OBQ,OAQ = OBQ  Using 2     OQ = OQ        common      QA = QB        Using 1OAQ  OBQ    RHSOQA = OQB   CPCTOQA = OQB = 12AQB = 12×60° = 30°In OAQ,cos 30° = basehypotenuse = AQOQ32 = 3OQOQ = 23 cm

  • 0
What are you looking for?