3 distinct coins are tossed together. Find the probability of getting---
a ) at least two heads.
b) at most two heads.
Please Elaborate .

 

Dear Student,

Refer the following link :

https://www.meritnation.com/ask-answer/question/three-unbiased-coins-are-tossed-what-is-the-probability-of-g/probability/481479

Hope this would clear your doubt.

Do let us know in case of any further concerns.

Regards

  • 0
Total no. of outcome = HHH, HHT, HTH, HTT, THH, THT, TTH, and TTT.= 8

1.At least two heads = { HHH, HHT, HTH, THH, } = 4
Required Probability = 4/8 = 1/2

2. At most one head = {HHH, HHT, HTH, HTT, THH, THT, TTH} = 7
Required Probability = 7/8

Hope It Helps!!!
  • 2
total outcomes=8
TTH; THT; TTT; THH; HTT; 
HTH; HHT; HHH
 
  1. AT LEAST TWO HEADS 
POSSIBLE OUTCOMES=THH ; HHH ; HTH ; HHT
P(AT LEAST TWO HEADS)=4/8                                            =1/2​
2. AT MOST TWO HEADS 

POSSIBLE OUTCOMES=THH ; THT ; TTT ; TTH ;
HTH ; HHT ; HTT
P(AT MOST TWO HEADS) = 7/8

HOPE THIS HELPS
  • 2
What are you looking for?