a 110 - V household circuit that contains an 1800 - W microwave, a 1000 - W toaster, and an 800 - W coffeemaker is connected to a 20 - A fuse. determine the current. will the fuse melt if the microwave and the coffeemaker are both on?  

Dear Student,

Please find below the solution to the asked query:

The current in the fuse if all appliances are on will be $i=\frac{P}{V}=\frac{1800+1000+800}{110}=32.77 \text{A}$. 
If microwave and coffee maker both are on then current is $i=\frac{P}{V}=\frac{1800+800}{110}=23.63 \text{A}$, Since the fuse is for lower current the fuse will melt. 

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