A 1800 Kg car is moving at 30m/s. when brakes are applied. If the average force

exerted by the brakes is 6000N, find the distance travelled by the car before it
comes to rest?

Force = ma

-6000 N = ma 

a = -6000/1800 = -10/3 m/s2

u = 30 m/s  and v = 0 m/s

Using the equation of motion,

v2 - u2 = 2as

0 - 30×30 =-2×(10/3)×s

s = 135 m

  • 15

F = ma

6000 = 1800 * a

a = 10 / 3 m/s^2

Using third equation of motion

v2 = u2 + 2as

0 = 30*30 + 2* 10/3 * s

-900 =  20s/3

s = -900 * 3 / 20

s = -135 m

Ignoring - sign

The car moved 135 m.

  • 6

 Ans: 135 m

  • -1
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