a bag contains 25 paisa and 50 paisa coins whose total value is rs. 30 . if the number of 25 paisa coin is four times that of 50 paisa coin . find the no. of each type of coins?
Let number of 25 paise coins = x, number of 50 paise coins = y
25x + 50y = 3000 (given 30 rs = 3000 paise)
On diiding by 25, eqn becomes x + 2y = 120
Also x = 4y (given)
Substituting in tht eqn, 4y + 2y = 120 => 6y = 120 => y = 20
So x = 120 - 2y = 120 - 2(20) = 80
So 80 coins of value 25 p, and 20 coins of value 50 p.
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50 paise coins- x
Total value- rupees 30.
First we need to convert everything in one unit. Either the passage in coins or the rupees in paisa.
30 rupees equal to 3000 paisa.
Now, 50*1=50 and 25*4=100
So now, 100+50= 150
The divide it, 3000/150= 20
So 50 paisa coins are 20 and the 25 paisa coins are 20*4=80