a bag contains 25 paisa and 50 paisa coins whose total value is rs. 30 . if the number of 25 paisa coin is four times that of 50 paisa coin . find the no. of each type of coins?

the 25 paise coins are-80

and 50 paise coins are -20

ok

- 8

Let number of 25 paise coins = x, number of 50 paise coins = y

25x + 50y = 3000 (given 30 rs = 3000 paise)

On diiding by 25, eqn becomes x + 2y = 120

Also x = 4y (given)

Substituting in tht eqn, 4y + 2y = 120 => 6y = 120 => y = 20

So x = 120 - 2y = 120 - 2(20) = 80

So 80 coins of value 25 p, and 20 coins of value 50 p.

- 3

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- -5

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- 0

50 paise coins- x

Total value- rupees 30.

First we need to convert everything in one unit. Either the passage in coins or the rupees in paisa.

30 rupees equal to 3000 paisa.

Now, 50*1=50 and 25*4=100

So now, 100+50= 150

The divide it, 3000/150= 20

So 50 paisa coins are 20 and the 25 paisa coins are 20*4=80

- 0