a block of mass 2 kg rests on a rough inclined plane making an angle 30degrees with the horizontal . the coeffecient of static friction between the block and the plane is 0.7 . the frictional force on the block is??
Given, m = 2 kg
θ = 300
μ = 0.7
As it is clear for figure :
R = m g cos θ
Therefore, force of friction, F = μ R = μ m g cos θ = 0.7 X 2 X 9.8 X cos 300 = 11.86 N
θ = 300
μ = 0.7
As it is clear for figure :
R = m g cos θ
Therefore, force of friction, F = μ R = μ m g cos θ = 0.7 X 2 X 9.8 X cos 300 = 11.86 N