# A boy takes 10 min to walk from his house to the bus stop.if his average speed is 4km/h.estimate the distance of the bus stop from his house?

Dear student

$\mathrm{Given}\phantom{\rule{0ex}{0ex}}Timet=10min=10\times 60=600sec\phantom{\rule{0ex}{0ex}}averagevelocityv=4km/hr=4000/3600m/s=1.11m/s\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}velocity=\frac{dis\mathrm{tan}ce}{time}\phantom{\rule{0ex}{0ex}}dis\mathrm{tan}ce=velocity\times time\phantom{\rule{0ex}{0ex}}dis\mathrm{tan}ce=1.11\times 600=666m=0.666km\phantom{\rule{0ex}{0ex}}Dis\mathrm{tan}cebetweenbusstopandhouse=0.666km\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}Regards\phantom{\rule{0ex}{0ex}}$

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