A boy takes 10 min to walk from his house to the bus stop.if his average speed is 4km/h.estimate the distance of the bus stop from his house?


Dear student

GivenTime t= 10 min = 10×60=600secaverage velocity v=4km/hr=4000/3600 m/s=1.11 m/svelocity=distancetimedistance =velocity×timedistance=1.11×600=666 m =0.666 kmDistance between bus stop and house = 0.666 kmRegards

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