A boy tries to hit a bird by throwing stone vertically upward but the stone misses the bird. The stone goes upward in the air for 3s. While returning after 1s the stone hits the bird.
- Find the maximum height reached by the stone.
- At what height was the bird hit?
- What value is not shown by the boy?
From first equation of motion:
v = u-gt v=0 at topmost point taking g=10 m/s2
u = gt
= 3*10 = 30 m/s
now, from third equation of motion:
v2 = u2 -2gh
2*10*h=302
h = 45 m (ANS (i))
now, while returning u = 0 m/s and g = 10m/s2
applying second equation of motion height fell can be calculated as under:
h = ut + 1/2 gt2
h = 0*t + 1/2 *10*1
height fell = 5m (ANS (ii))
(iii) The boy has not shown the angle at which he threw the stone.
v = u-gt v=0 at topmost point taking g=10 m/s2
u = gt
= 3*10 = 30 m/s
now, from third equation of motion:
v2 = u2 -2gh
2*10*h=302
h = 45 m (ANS (i))
now, while returning u = 0 m/s and g = 10m/s2
applying second equation of motion height fell can be calculated as under:
h = ut + 1/2 gt2
h = 0*t + 1/2 *10*1
height fell = 5m (ANS (ii))
(iii) The boy has not shown the angle at which he threw the stone.