A bridge in the shape of straight path, across a river ,makes an angle of 300 with the width of the river. If the length of the bridge is 100 m then find the width of the two river.




Let AB is the width of the river.Let AC be the bridge. Now, AC = 100 mLet CAB = 30°Now, in ABC, we have cos A = basehypotenusecos 30° = ABAC32 = AB1002AB = 1003AB = 10032AB = 503So, width of the river, AB = 503 m

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