# a copper wire 3mm in diameter ,is wound about a cylinder whose length is 12cm , and diameter 10cm so as to cover the csa of the cylinder . find the length and mass of the wire , assuming the density of copper to be 8.88g per cm3

It can be observed that 1 round of wire will cover 3 mm height of cylinder.
Length of wire required in 1 round = Circumference of base of cylinder
= 2πr = 2π × 5 = 10π
Length of wire in 40 rounds = 40 × 10π
= 1257.14 cm = 12.57 m

Radius of wire= .0.3/2 = 0.15

Volume of wire = Area of cross-section of wire × Length of wire

= π(0.15)2 × 1257.14
= 88.898 cm3
Mass = Volume × Density
= 88.898 × 8.88
= 789.41 gm
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A copper wire 3mmin diameter is wound about a cylinder whose length 1.2m and diameter10 cm so as to cover the curved surface area of the cylinder .find the length of wire
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No
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12571.4 cm
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1256 cm is the length of the wire
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Ookk
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Hello
• -25
Ans

• -24
By Manit Gera...

• 2
Hi
• -15
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No
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Length of wire required in 1 round = Circumference of base of cylinder = 2πr = 2π × 5 = 10π Length of wire in 40 rounds = 40 × 10π = 1257.14 cm = 12.57 m Radius of wire= .0.3/2 = 0.15 Volume of wire = Area of cross-section of wire × Length of wire = π(0.15)2 × 1257.14 = 88.898 cm3 Mass = Volume × Density = 88.898 × 8.88 = 789.41 gm
• 9
say

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can be observed that 1 round of wire will cover 3 mm height of cylinder. Length of wire required in 1 round = Circumference of base of cylinder = 2πr = 2π × 5 = 10π Length of wire in 40 rounds = 40 × 10π = 1257.14 cm = 12.57 m Radius of wire= .0.3/2 = 0.15 Volume of wire = Area of cross-section of wire × Length of wire = π(0.15)2 × 1257.14 = 88.898 cm3 Mass = Volume × Density = 88.898 × 8.88 = 789.41 gm
• 2
It can be observed that 1 round of wire will cover 3 mm height of cylinder.

Length of wire required in 1 round = Circumference of base of cylinder
= 2πr = 2π × 5 = 10π
Length of wire in 40 rounds = 40 × 10π

= 1257.14 cm = 12.57 m

Radius of wire= .0.3/2 = 0.15

Volume of wire = Area of cross-section of wire × Length of wire