A hemispherical bowl has a thickness of 2 cm. The outer diameter of the bowl is 12 cm.How much water can be contained in the bowl?

Outer diameter of hemispherical bowl = 12 cm
Then its radius = $\frac{12}{2}$ = 6 cm
And thickness = 2 cm
So inner radius of hemispherical bowl = 6 cm - 2 cm = 4 cm
So volume of  inner hemispherical bowl = $\frac{2}{3}{\mathrm{\pi r}}^3 = \frac{2}{3}\times \frac{22}{7}\times {\left(4\right)}^3 = \frac{2\times 22\times 64}{21} = 134.095 {\mathrm{cm}}^3$
Therefore the amount of water in the bowl is 134.095 cubic centimetre.