A hemispherical bowl has a thickness of 2 cm. The outer diameter of the bowl is 12 cm.How much water can be contained in the bowl?

Then its radius = $\frac{12}{2}$ = 6 cm

And thickness = 2 cm

So inner radius of hemispherical bowl = 6 cm - 2 cm = 4 cm

So volume of inner hemispherical bowl = $\frac{2}{3}{\mathrm{\pi r}}^{3}=\frac{2}{3}\times \frac{22}{7}\times {\left(4\right)}^{3}=\frac{2\times 22\times 64}{21}=134.095{\mathrm{cm}}^{3}$

Therefore the amount of water in the bowl is 134.095 cubic centimetre.

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