A man is walking along a straight road. He notices the top of a tower subtending an angle A=60degree with the ground at the point where he is standing. If the height of the tower is h=25m, then what is the distance (in met ers) of the man from the tower?



Let C be the point where the man is standing on the ground.Let AB be the tower of height 25 m.Let ACB = 60°In ABC,tan 60° = ABBC3 = 25BCBC = 253 = 253×33 = 2533 = 25 × 1.7323 = 43.33=14.43 m

So, the man is standing at a distance of 14.43 m from the tower.

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