A park, in the shape of a quadrilateral ABCD,has angle C=90', AB=9m,BC=12m,CD=5m and AD=8m. how much area deos it occupy?

In right angled triangle BCD,

Area of quadrilateral ABCD = Area of ΔABD + Area of ΔBCD ...... (1)

Now, Area of ΔBCD = × Base × Height

In ΔABD, AB = 9m

BD = 13m

and AD = 8m

By Heron's Formula,

Hence from (1),

Area of Quadrilateral ABCD = (30 + 35.497)m^{2}

= 65.497 m^{2}

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