a PARTICLE IS PROJECTED FROM GROUND WITH SPEED 80 m/s AT AN ANGLE 30 DEGREE WITH HORIZONTAL FROM GROUND .THE MAG NITUDE OF AVERAGE VELOCITY OF PARTICLE IN TIME T=2SEC TO T=6SECS IS?

Given, u = 80 m/s
θ = 300
Distance travelled by the particle along horizontal direction in t = 2 s is given by :
x1 = u cos θ t1
x1 = 80 X cos 300 X 2 = 80 3 m.

Distance travelled by the particle along horizontal direction in t = 6 s is given by :
x2 = u cos θ t2
​x2 = 80 X cos 300 X 6 = 240 3 m
​Magnitude of avg. velocity of particle in time t = 2 s to t = 6 s is :
v = Δ xΔ t = x2 - x1t2 - t1 = 240 3 - 80 36-2 = 403 m/s
 

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