# a person is listening to a tone of 500 Hz sitting at a distance of 450m from the source of the sound . What is the time interval between successive compressions from the source ?

f=500Hz

distance=450m

T=1/f=1/500=0.002s

• 51

f=500Hz

S=450m

T=1/f=1/500=0.002s

• 3

Remeber tone is a sound of single frequency.

Tone = 500Hz

Therefore by this statement, we know that the wave can travel 500m in 1 second because a tone is a single frequency.distance or wavelength is given as 450 m

Therefore Distance / Speed = time

450/500=0.9 sec

• -7

• -8
find the frictional force required to stop a car of mass 500kg over a distance of 50m ,if the initial speed is 72km/hr. also find its initial KE.find the work done in bringing the car to rest
• -9
See basically, distance is given just to confuse you,Don't get confused Frequency=1/time and therefore, time=1/frequency,So it's 1/500= 0.002 seconds
• 20
9gag

• -17
A person has a hearing range from 20 Hz to 20KHz what are the typical wavelength of sound waves in air corresponding to these two frequencies.take the speed of sound in air is 344m/s.
• -12
this is correct ans. • 28
0.002s
• 2
frequency=1/time
500Hz=1/time
500Hz × time = 1
time = 1/500
time= 0.002sec

hope this answer helps u     :)
• 14
Just ignore the distance,it is useless.Then you can solve it easily.

• -1
speed= wavelength *frequency
let wavelength be ""x" meter
500= 340 x
​x= 500/340=1.47 meter

• 0
0.002s
• -2
Frequency (v)=500Hz Frequency =1/t T=1/frequency =1/500 =0.002 sec Thus time interval between two consecutive compression of the given wave = 0.002 sec
• 2
This will be the right ans... Hope it will help u • 1
Physical
• 1 • 1 • 0
f=500Hz

distance=450m

T=1/f=1/500=0.002s
• 0
Sorry no idea...:(
• 0
2.0seconds
• 0
What are you looking for?