a person is listening to a tone of 500 Hz sitting at a distance of 450m from the source of the sound . What is the time interval between successive compressions from the source ?

Therefore by this statement, we know that the wave can travel 500m in 1 second because a tone is a single frequency.distance or wavelength is given as 450 m

Therefore Distance / Speed = time

450/500=0.9 sec

-7

Souja Liakath answered this

i need expert answer

-8

Manju answered this

find the frictional force required to stop a car of mass 500kg over a distance of 50m ,if the initial speed is 72km/hr. also find its initial KE.find the work done in bringing the car to rest

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Prasoon Agrawal answered this

See basically, distance is given just to confuse you,Don't get confused Frequency=1/time and therefore, time=1/frequency,So it's 1/500= 0.002 seconds

20

Faraz Cmk answered this

9gag

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Laksmipriya answered this

A person has a hearing range from 20 Hz to 20KHz what are the typical wavelength of sound waves in air corresponding to these two frequencies.take the speed of sound in air is 344m/s.

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Mamta Bansal answered this

this is correct ans.

28

Osman answered this

0.002s

2

Charishma C answered this

frequency=1/time
500Hz=1/time
500Hz × time = 1
time = 1/500
time= 0.002sec

hope this answer helps u :)

14

Luqman.s answered this

Just ignore the distance,it is useless.Then you can solve it easily.

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Neeraj Sreenivasan answered this

speed= wavelength *frequency
let wavelength be ""x" meter
500= 340 x
x= 500/340=1.47 meter

0

Sandya answered this

0.002s

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Shreya answered this

Frequency (v)=500Hz
Frequency =1/t
T=1/frequency
=1/500
=0.002 sec
Thus time interval between two consecutive compression of the given wave = 0.002 sec