A projectile is launched at time t=0 with velocity=20m/s at an angle 53 with the horizontal . the magnitude of velocity of the projectile at the highest point of the trajectory is

Dear Student,
initial velocity, u = 20 m/s.
At the highest point the vertical component of the velocity will become 0. The particle has only the horizontal component of velocity which is ucos53o=20×35=12 m/s at an angle 0o wrt the horizontal.

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