A sample of dolomite contained 45% of CaCO3 , 40% of MgCO3 and 15%clay. Calculate the mass of sulphuric acid of 30% strength required to react completely with 10g of the sample.
experts please give me the answer as soon as possible. its urgent..please...
In 10 g sample of dolomite, mass of CaCO3 = 45% of 10 g = 4.5 g
Mass of MgCO3 = 40 % of 10 g = 4 g
Mass of clay = 1- (4.5+ 4) = 1.5g
Since clay is a physical impurity, it will not react.
Therefore, 10 g sample contains 4.5 + 4 = 8.5 g dolomite.
Reaction between dolomite and sulphuric acid:
CaCO3 + MgCO3 + 2H2SO4 → CaSO4 + MgSO4 +2 H2O + 2CO2
Now, 184 g of dolomite reacts with 2 moles = 196 g of H2SO4
8.5 g of dolomite reacts with of H2SO4
Let A g of 30% sulphuric acid is required to react with 10 g sample.
100 x 9 = 30 x A
= 30 g
Therefore, 30 g of 30% sulphuric acid is required to completely react with 10 g of sample.
for remaining one please ask in separate thread.