a source of sound is placed at one end of an iron bar 2km long and 2 sounds are heard at the other end at an interval of 5.6 s. if the velocity of sound in air is 330m/s , find the time taken by sound to travel 2 km in iron and the velocity of sound in iron.
Given that
Speed of sound in air (V a ) = 330 m/s
Speed of sound in iron Vi = ?
Distance L = 2 km = 2000 m
Let t 1 = Time taken by sound in air
t 2 = Time taken by sound in iron
(1)
Δt = t 1 – t 2 = 5.6 s
Now,
t 2 = t 1 – Δt = 6.06 – 5.6 = 0.46 s
(2)