A spehrical glass bulb of radius 100cm contains a concentric balloon that contains some N2 gas and the remaining space in the glass bulb contains 50g of H2 .In the given conditions ,radius of the rubber balloon was found to be 40cm .Now the seal of the glass bulb was opened and 26g of H2 (g) was further added and resealed .Assuming constant temperature through out ,if the radius of the rubber balloon in the new radius is 7x ,then what is x.?

Dear Student,



Therefore, the new radius is 7x = 7 × 5.25
                                                        = 36.75 cm

Regards

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