A varies jointly as B and C, and A =6 when B=3 and C = 2. For B=5 and C=7, find A

We have,A varies jointly with B and C. ThenA = kBC , where k is the constant of proportionalityPut A = 6, B = 3, C = 2 in above equation, we get6 = k× 3 × 2k = 1Now, put k = 1, C = 7, B = 5 in the above equation, we getA = 1 × 5× 7 = 35So, A = 35

  • 0
What are you looking for?