A vessel of negligible heat capacity contains 40g ice at 0 C 8g of steam at 100 C is passed - Science - Heat

Question

A vessel of negligible heat capacity contains 40g ice at 0 ° C
8g of steam at 100 ° C is passed into the ice to melt it Find
the final temperature of the mixture (Latent heat of ice =
336Jg-1, Latent heat of steam = 2268Jg-1 SP
heat capacity of water = 4 2 Jg1ºC )

Ravjot Kaur · Accepted Answer

Dear student
Please find below the solution to the asked query:
Let final temperature of the mixture is θmass of steam, m=8gmass of ice, m' =40glatent heat of vapourisation of steam, L=2268J/gLatent heat of fusion of ice, L'=336J/gSpecific heat capacity of water =4
2J/gHeat given by system= Heat taken by the icemL+mC∆θ= m'L' +m'C'∆θ8×2268+8×4
2×(100-θ)=40×336+40×4
2×(θ-0)18144+3360-33
6×θ =13440 +168×θ201
6×θ =8064θ=40oC

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A vessel of negligible heat capacity contains 40g ice at 0 ° C.8g of steam at 100 ° C is passed into the ice to melt it. Find the final temperature of the mixture (Latent heat of ice = 336Jg-1, Latent heat of steam = 2268Jg-1. SP. heat capacity of water = 4.2 Jg1ºC.)

A vessel of negligible heat capacity contains 40g ice at 0 $°$ C.8g of steam at 100 $°$ C is passed into the ice to melt it. Find the final temperature of the mixture (Latent heat of ice = 336Jg^-1, Latent heat of steam = 2268Jg^-1. SP. heat capacity of water = 4.2 Jg^1ºC.)