a200 is the 200th term of the AP x, x+0.34, x+0.68, x+1.02....... and b200 is the 200th term of the AP Y, Y+0.34 , Y+0.68, Y+1.02
IT IS GIVEN THAT X+Y=7 and a200 -b200 = 0.124 find x & y
Dear Student!!
Here is the answer to your query.
Given two A. P.'s :
I) x, x + 0.34, x + 0.68, x + 1.02, ...
II) y, y + 0.34, y + 0.68, y + 1.02, ...
a200 is the 200th term of A. P. I & b200 is the 200th term of A. P. II.
It is given that: x + y = 7 and a200 – b200 = 0.124.
For Ist A.P. :
a1 = x, a2 = x + 0.34
Common difference (d) = a2 – a1 = (x + 0.34) – x = 0.34
For IInd A.P.:
b1 = y, b2 = y + 0.34
Common difference (D) = b2 – b1 = (y + 0.34) – y = 0.34
Now, a200 – b200 = 0.124
⇒ a + 199d – (b + 199D) = 0.124
⇒ a + 199 (0.34) – b – 199 (0.34) = 0.124
Adding (1) & (2),
2x = 7.124
Putting the value of x in (2), we get y = 7 – x = 7 – (3.562) = 3.438
Hence, x = 3.562 and y = 3.438.
Cheers..!!