ABCD is a cyclic quadrilateral in which AC and BD are its diagonals. If angleDBC = 55° and angle BAC = 45°, find BCD.
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Given: ∠BAC = and ∠DBC =
∠DBC = ∠DAC = (angles in the same segment made by chord CD)
∠A = ∠DAC + ∠BAC = + =
Since opposite angles of a cyclic quadilateral are supplementary,
∠A + ∠BCD =
If AB = BC,
∠ACB = ∠BAC =
∠ECD = ∠BCD – ∠ACB =
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Given : angle BAC = 45 degree and angle DBC = 55 degree