ABCD is a parallelogram. DE is perpendicular to AB, AB = 30cm, DE = 15cm and BC = 25cm. Find the length of DF, where DF is perpendicular to BC.
Answer :
We have ABCD is a parallelogram , DE perpendicular to AB ,
AB = 30 cm
DE = 15 cm
And
BC = 25 cm
We know area of parallelogram = Base Height
And we take AB as base so DE is height of parallelogram ABCD
So,
Area of ABCD = 30 15 = 450 cm2 --------------- ( 1 )
And as give DF is perpendicular on BC , SO if we take BC as base , so DF is height of parallelogram ABCD
And
Area of ABCD = 25 DF ----------------- ( 2 )
Now we equate equation 1 and 2 and get
25 DF = 450
DF = = 18 cm ( Ans )
We have ABCD is a parallelogram , DE perpendicular to AB ,
AB = 30 cm
DE = 15 cm
And
BC = 25 cm
We know area of parallelogram = Base Height
And we take AB as base so DE is height of parallelogram ABCD
So,
Area of ABCD = 30 15 = 450 cm2 --------------- ( 1 )
And as give DF is perpendicular on BC , SO if we take BC as base , so DF is height of parallelogram ABCD
And
Area of ABCD = 25 DF ----------------- ( 2 )
Now we equate equation 1 and 2 and get
25 DF = 450
DF = = 18 cm ( Ans )