ABCD is a parallelogram in which BC is produced to E such that CE =BC. AE intersects CD at F . Show that area OF TRIANGLE BDF = 1/3 of area(ABCD).

Question

ABCD is a parallelogram in which BC is produced to E such that
CE =BC AE intersects CD at F Show that area OF TRIANGLE BDF = 1/3
of area(ABCD)

Chetna Khanna · Accepted Answer

Please refer to the following link to get answer to your
question

https://www meritnation
com/ask-answer/question/in-the-figure-abcd-is-a-parallelogram-in-which-bc-is-produc/areas-of-parallelograms-and-triangles/1793669
The reason given in fourth step is wrong The correct statement
is:
If a triangle and a parallelogram are on the same base and
between the same parallels, the area of the triangle is equal to
half of the parallelogram