ABCD is a parallelogram with perimeter 40cm. Find the value of x and y if AB=3x, BC= 2x, CD= 2y+2, AD= 2x Share with your friends Share 6 Manbar Singh answered this ABCD is a parallelogram with perimeter 40 cmand AB = 3x, BC = 2x, CD = 2y + 2and AD = 2xPerimeter of ∥gm ABCD, P = AB + BC + CD + DA P = 3x + 2x + 2y + 2 + 2x P = 7x + 2y + 2⇒ 40 = 7x + 2y + 2⇒ 7x + 2y = 40 - 2⇒ 7x + 2y = 38 ..............1Also AB = CD opposite sides of parallelogram are equal⇒ 3x = 2y + 2⇒ 3x - 2y = 2 ..............2Adding equation 1 and 2, we get 10x = 40⇒ x = 4010 = 4Putting the value of x in equation 1, we get 7× 4 + 2y = 38⇒ 28 + 2y = 38⇒ 2y = 38 - 28⇒ 2y = 10⇒ y = 102⇒ y = 5 ∴ x = 4and y = 5 7 View Full Answer Abhilash answered this Since it is a parellolagram, 3x should be equal tp 2y+2.So, 3x+2x+3x+2x = 40ie, 10x = 40x = 40/10= 4So, side AB = 3x =3*4=12DC=3x=2y+2=12ie, 2y=12-2=10y=5. 2
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