Given:
- ABCD is a rhombus. Therefore AB = BC = CD = AD.
- angle DAB = 70 degree
To find: angle BDC
Solution: angle DAB = angle DCB = 70degree [ Opposite angles of a IIgm ]
In triangle BDC, BC = DC [ Given ]
Therefore angle BDC = angle CBD =x [ Angles opposite to equal sides are equal ]
Applying angle sum property in this triangle,
2x + 70 = 180
2x = 110
x = angle BDC = 55 degree.
HOPE THIS HELPS !!!