ABCD is a rhombus if angle DAB=70 degree , then find angle CDB.

Given, ABCD is a rhombus and

Since, ABCD is a rhombus.So

And we know that,

Thus,

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 Given:

  • ABCD is a rhombus. Therefore AB = BC = CD = AD.
  • angle DAB = 70 degree 

To find: angle BDC

Solution: angle DAB = angle DCB = 70degree [ Opposite angles of a IIgm ]

In triangle BDC, BC = DC [ Given ]

Therefore angle BDC = angle CBD =x [ Angles opposite to equal sides are equal ]

Applying angle sum property in this triangle,

2x + 70 = 180

2x = 110

x = angle BDC = 55 degree.

HOPE THIS HELPS !!!

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