ABCD is a square and ABE is an equilateral triangle outside the square then find angle BEC?



Since ABCD is a square abd ABE an equilateral triangle so AB=BE=AE=BC=CD=ADSo in triangle BCE, BCE=BEC Since BE=BCSo using angle sum property in triangle BEC,x+x+90+60=1802x=30x=15 degreeSo angle BEC is 15 degree

  • 4
60
  • 1
What are you looking for?