An isosceles right angle triangle has area 8 cm square.Find it's hypotenuse..
Answer it quickly..
Dear student,
In an isosceles triangle two sides are equal.
Both the perpendicular and base are equal in length.
So Area of triangle = 1/2 x b x h
Let b = h = y
Area=1/2 * y * y = 8
y² = 16
y = 4 cm
So Perpendicular = Base = 4 cm
Now by Pythagoras theorem,
Hypotenuse=√(Perpendicular2+Base2)=√4² + 4² = √ 16+ 16 = √32 = 4√2 cm
So required hypotenuse = 4√2 cm
Regards
In an isosceles triangle two sides are equal.
Both the perpendicular and base are equal in length.
So Area of triangle = 1/2 x b x h
Let b = h = y
Area=1/2 * y * y = 8
y² = 16
y = 4 cm
So Perpendicular = Base = 4 cm
Now by Pythagoras theorem,
Hypotenuse=√(Perpendicular2+Base2)=√4² + 4² = √ 16+ 16 = √32 = 4√2 cm
So required hypotenuse = 4√2 cm
Regards