By means of graph verify that the point (1-1) is a solution of the equation 3x+2y-1=0 2x+y-1=0 - Maths - Linear Equations in Two Variables

Question

By means of graph verify that the point (1-1) is a solution of
the equation 3x+2y-1=0 2x+y-1=0

Lalit Mehra · Accepted Answer

Dear Student!

The given equation are 3x + 2y – 1 = 0 and 2x + y – 1 = 0.

Consider the equation 3x + 2y – 1 = 0.

3x + 2y – 1 = 0

⇒ 2y = 1 – 3x

$\Rightarrow y = \frac{1 - 3 x}{2} When x = 1, y = \frac{1 - 3 \times 1}{2} = \frac{1 - 3}{2} = \frac{- 2}{2} = - 1 When x = 3, y = \frac{1 - 3 \times 3}{2} = \frac{1 - 9}{2} = \frac{- 8}{2} = - 4 When x = - 1, y = \frac{1 - 3 \times (- 1)}{2} = \frac{1 + 3}{2} = \frac{4}{2} = 2$

Thus we have the following table,

$\begin{matrix} x & 1 & 3 & - 1 \\ y & - 1 & - 4 & 2 \end{matrix}$

Consider the equation 2x + y – 1 = 0

2x + y – 1 = 0

⇒ y = 1 – 2x

When x = 1, y = 1 – 2 × 1 = 1 – 2 = – 1

When x = 2, y = 1 – 2 × 2 = 1 – 4 = – 3

When x = –1, y = 1 – 2 × ( – 1) = 1 + 2 = 3

Thus, we have the following table,

$\begin{matrix} x & 1 & 2 & - 1 \\ y & - 1 & - 3 & 3 \end{matrix}$

The graph of the given linear equation is given as,

Thus, ( 1, –1) is the solution of the given equations.

Cheers!

3

Thus, ( 1, â€“1) is the solution of the given equations Cheers!