Calculate the molality of 1M solution of sodium nitrate. The Density of the solution is 1.25g/ml.

Molarity of the solution = 1 M

Density of the solution = 1.25 g/mL

Mass of NaNO

_{3}in 1L of the solution = 1 x 65 = 65 g

Mass of 1 L of the solution = 1000 x 1.25

= 1270 g

Thus,

Mass of water in the solution = 1250 - 65

= 1185 g

Hence,

Molality = Number of moles of solute / Mass of solvent in kg

= 1 / 1.185 =

**0.844 m**

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