Calculate the wave number for the shortest wavelength transition in the lyman series of atomic hydrogen. (Rydberg constant=109677 /cm)

n =    = R (  -  )

   n₁ = 1(Lyman series)  n₂ = 2  R = 1.0 x 10^-7 meter ^-1

Putting the value in above formula, we get the wave number “n” of hydrogen atom.

   n = 0.5 x 10^-7 m^-1.